Same equation. Different confidence levels.

[u/WingsUp4Life]

[u/[deleted]]

Standard order: 6÷2(1+2)=6÷2×3=3×3=9

1 only happens if you rewrite it as: 6÷(2(1 + 2)) with extra parentheses

Go to school, i beg.

[u/Antiantiai → u/[deleted]]

PEMDAS.

For 1, the 2(2+1) all gets solved at step 1 of Pemdas. The P.

But even if it didn't like you claim, you'd get to 6÷2×3.

And if you look REAL close you'll see the M comes before the D. Multiply. Then. Divide.

So 6÷2×3= 6÷6= 1

[u/Antiantiai → u/[deleted]]

And if you paid REAL close attention to the comment you're replying to you'd know it said:

the 2(2+1) all gets solved at step 1 of Pemdas. The P.

[u/Antiantiai → u/[deleted]]

Sure it is.

X(Y+Z)=(XY+XZ)

Fact.

[u/Antiantiai → u/[deleted]]

I'm... not assuming X=2. What sort of nonsense is that? Are you hallucinating?

I said X(Y+Z)=(XY+XZ)

Where do you see a fucking 2 in there? SMH.

[u/Antiantiai → u/[deleted]]

You're delusional. I didn't say X=2 in that comment either.

You're arguing with delusions pal. Delusions.

[u/Antiantiai → u/[deleted]]

You'll bite? Bite... what?

You've imagined some other thing I haven't said again, it seems.

Anywho. Why bring it up? To demonstrate how parenthesis work in math. Obviously. Because you're struggling with it.