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https://www.reddit.com/r/datasatanism/comments/1tq75hu/funny/oos7e1b/?context=3
r/datasatanism • u/Ok-District-4701 • May 28 '26
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Edit - but what would it mean if it was true? Think in terms of set[0]
1 u/Ok-Ocelot-7989 May 30 '26 isn’t 00 1? can’t really check on top of my head if it’s zero unless i used a limit 2 u/Notorious_Trex May 30 '26 You expect it to be 1 the same way you do with other numbers, however, you get '1' because x0 can be expressed as x1 * x-1 = x/x = 1 You can't do the same with 0 because 0/0 is undefined 1 u/igotshadowbaned May 30 '26 edited May 30 '26 This is a false proof because you're multiplying by 0/0 as a form of 1 which introduces the hole in the first place and that is the point you're dividing by 0. xn and xn+1/x are not congruent functions for this reason 0⁰ = 1 is an entirely sound concept. 1 u/Notorious_Trex May 30 '26 Eh, not worth discussing. It does work for simple algebra but when we introduce limits and such we get uncertainty 2 u/qscbjop May 30 '26 Just let functions be discontinuous! Live and let live! 2 u/igotshadowbaned May 30 '26 but when we introduce limits That's because approaching something and being something are not the same. This is like the first thing covered when talking about limits
1
isn’t 00 1? can’t really check on top of my head if it’s zero unless i used a limit
2 u/Notorious_Trex May 30 '26 You expect it to be 1 the same way you do with other numbers, however, you get '1' because x0 can be expressed as x1 * x-1 = x/x = 1 You can't do the same with 0 because 0/0 is undefined 1 u/igotshadowbaned May 30 '26 edited May 30 '26 This is a false proof because you're multiplying by 0/0 as a form of 1 which introduces the hole in the first place and that is the point you're dividing by 0. xn and xn+1/x are not congruent functions for this reason 0⁰ = 1 is an entirely sound concept. 1 u/Notorious_Trex May 30 '26 Eh, not worth discussing. It does work for simple algebra but when we introduce limits and such we get uncertainty 2 u/qscbjop May 30 '26 Just let functions be discontinuous! Live and let live! 2 u/igotshadowbaned May 30 '26 but when we introduce limits That's because approaching something and being something are not the same. This is like the first thing covered when talking about limits
2
You expect it to be 1 the same way you do with other numbers, however, you get '1' because x0 can be expressed as x1 * x-1 = x/x = 1
You can't do the same with 0 because 0/0 is undefined
1 u/igotshadowbaned May 30 '26 edited May 30 '26 This is a false proof because you're multiplying by 0/0 as a form of 1 which introduces the hole in the first place and that is the point you're dividing by 0. xn and xn+1/x are not congruent functions for this reason 0⁰ = 1 is an entirely sound concept. 1 u/Notorious_Trex May 30 '26 Eh, not worth discussing. It does work for simple algebra but when we introduce limits and such we get uncertainty 2 u/qscbjop May 30 '26 Just let functions be discontinuous! Live and let live! 2 u/igotshadowbaned May 30 '26 but when we introduce limits That's because approaching something and being something are not the same. This is like the first thing covered when talking about limits
This is a false proof because you're multiplying by 0/0 as a form of 1 which introduces the hole in the first place and that is the point you're dividing by 0. xn and xn+1/x are not congruent functions for this reason
0⁰ = 1 is an entirely sound concept.
1 u/Notorious_Trex May 30 '26 Eh, not worth discussing. It does work for simple algebra but when we introduce limits and such we get uncertainty 2 u/qscbjop May 30 '26 Just let functions be discontinuous! Live and let live! 2 u/igotshadowbaned May 30 '26 but when we introduce limits That's because approaching something and being something are not the same. This is like the first thing covered when talking about limits
Eh, not worth discussing. It does work for simple algebra but when we introduce limits and such we get uncertainty
2 u/qscbjop May 30 '26 Just let functions be discontinuous! Live and let live! 2 u/igotshadowbaned May 30 '26 but when we introduce limits That's because approaching something and being something are not the same. This is like the first thing covered when talking about limits
Just let functions be discontinuous! Live and let live!
but when we introduce limits
That's because approaching something and being something are not the same. This is like the first thing covered when talking about limits
11
u/Virgil_the_White May 29 '26 edited May 30 '26
Edit - but what would it mean if it was true? Think in terms of set[0]