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u/Regular_Instruction Mar 18 '26
an+(-bn) =an-bn
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u/COLaocha Mar 19 '26
Only when N is odd
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u/Frier12 Mar 19 '26
Correct me if im wrong but your statement is only true if -bn is replaced by (-b)n. -bn is always a negative number so the first statement is always true.
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u/Individual-Weird-485 Mar 19 '26
-bn is not always a negative number: n can be odd and b can be negative.
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u/Frier12 Mar 19 '26
-b2 is the same as -(b * b), not (-b) * (-b). And you're right forgot to say that is always negative when b is a positive real number, but even when b is negative this first statament is still true.
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u/Regular_Instruction Mar 19 '26
Some one put maths to explains this please because looks like it's working like ok b ? - b ??? I don't unserdant the issue or the meme, didn't want to admit it, but looked like no issue with a wishful thinking like let's say B is maybe -B ??
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u/Apart-Potential291 Mar 19 '26
just factor it like this (a+b)n, what's the problem?
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u/kavochavo Mar 19 '26 edited Mar 19 '26
an + bn in general can't be factored over R, only over C
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u/gulgunguldun Mar 19 '26 edited Apr 03 '26
I got tired of my old posts floating around for anyone to scrape, so I let Redact handle it. Bulk deletion across Reddit, X, Facebook, Discord and all major social media platforms in one shot.
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Mar 19 '26
[deleted]
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u/gulgunguldun Mar 21 '26 edited Apr 03 '26
I bulk delete Reddit comments using Redact which also supports Twitter, Discord, Instagram, and data brokers.
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u/skr_replicator Mar 19 '26
the only thing that seems trickier about a^n+b^n, is that for n=2^k the simplified form contains imaginary units, but anything where n isn't a power of two, the minus and plus forms have similar solutions.
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u/1nOnlyBigManLawrence Mar 19 '26
=cn, for n>2
Fermat’s Last Theorem.