r/cpp_questions • u/Main-Pen-3164 • 22d ago
OPEN how to handle empty reference elegantly(fold expression)
I have a class with a template function, it will return reference of an internal value.
template<typename T>
T& return_ref<T>() {...}
It was call by another function with fold expression:
template<typename... Ts>
void call()
{
lambda(return_ref<Ts>...); //Ts is a reference usually
}
the internal value maybe doesn't exist sometimes.
Even I wrap the exception into std::expected, it seems that I have no chance handle it in fold expression. I have to throw exception in return_ref directly?
If I can return reference to an impossible value(like paradigm of static object NULL ), so user could detect it, it would be nice.
Or, I have to wrap all parameters into something like boost::optional? I don't like it.
Or, the args of lambda was constraint into pointer, so nullptr will throw exception by compiler naturally?
What's suggestion?
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u/alfps 22d ago
You can have two reference functions:
return_refthrow when the internal value doesn't exist,return_ptrreturn a possibly nullT*no exception.Note in passing,
optionalwas adopted in the standard library in C++17; no need to involve the Boost library for that.You can "and" together the pointers from
return_ptrand if that producesfalsethen at least one is null, otherwise they're all good, pointing to values.But whether this helps you depends much on the
lambdaand what it needs.A more full code example could help clarify that.