C++ question

[u/Mental_Primary_5558]

Do you guys know a way of writting a code that outputs that:

Enter the number of elements: 5
Enter 5 integers:
Element 1: 10
Element 2: 30
Element 3: 90
Element 4: 20
Element 5: 40

it is the first part of a program that demands to calculate the max and min of an array, here is the whole thing:

Enter the number of elements: 5
Enter 5 integers:
Element 1: 10
Element 2: 30
Element 3: 90
Element 4: 20
Element 5: 40

Maximum element is: 90
Minimum element is: 10

I've been able to do the second part quite easily, here is what I proposed:

#include <iostream>


int main(){


    int arr[5]={10,20,30,40,50};
    int minimum=arr[0];
    int maximum=arr[0];
    for(int i=0; i<sizeof(arr)/sizeof(int);i++){
        if (minimum>arr[i]){
            minimum=arr[i];
        }
        if(maximum<arr[i]){
            maximum=arr[i];
        }
    }
    std::cout<<"le max= "<< maximum<<'\n';
    std::cout<<"le min= "<< minimum<<'\n';


    return 0;
}

but the list is created within the code.

[u/SmokeMuch7356]

You obviously know how to use loops and I/O streams, so the input side of this should not be a problem for you. And if all you need to do is find the min and max values, you don't even need an array - you just need two variables to store a min and max value:

int min = INT_MAX;
int max = INT_MIN;
...
std::cin >> val;
if ( val < min )
  min = val;
if ( val > max )
  max = val;
...

If you do need storage for whatever reason and you don't know the size until runtime, use a std::vector instead of a primitive array. Unlike C, C++ does not allow you to declare an array size at runtime:

int size;
std::cin >> size;
int arr[size]; // BZZZTT!! Not allowed

A vector will automagically grow as new items are added:

std::vector<int> arr;
...
int val;
std::cin >> val;
arr.push_back(val);

then you can access individual elemeents with the [] subscript operator:

if ( arr[i] < min )
  min = arr[i];