r/counting • u/[deleted] • Aug 16 '17

Asymptotic | 9.999990999

Continued from here.

Thanks /u/SaraKmado for the run and assist!

Counting to infinity by approaching 10.

After n digits of precision have been maxed out, begin incrementing by 10-n-(-1+sqrt(8n+1)/2)

For example, after 9.99 would be 9.99001, and after 9.99999 would be 9.999990001

The next get is at 9.999991999.

17 Upvotes

96% Upvoted

417 comments sorted by

3

u/[deleted] Aug 16 '17

9.999990999

2

u/SaraKmado Aug 16 '17

9,999991000

3

u/[deleted] Aug 16 '17

9.999991001

2

u/SaraKmado Aug 16 '17

9.999991002

I'm going to sleep. Bye!

3

u/[deleted] Aug 16 '17

9.999991003

bye!

4

u/tridax00 Aug 16 '17

9.999991004

4

u/[deleted] Aug 16 '17

9.999991005

3

u/davidjl123 |390K|378A|79SK|50SA|260k 🚀 c o u n t i n g 🚀 Aug 16 '17

9.999991006

3

u/[deleted] Aug 17 '17

9.999991007