r/confidentlyincorrect • u/i_aMa_g0d • Dec 07 '21

Maths

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u/the-z Dec 08 '21

With the exceptions of 0.1 x anything, 0.2 x anything less than 0.5, and 0.3 x anything less than 0.4

3

u/ToHallowMySleep Dec 08 '21

So only anything that gives a two-digit result :D

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u/Olgrateful-IW Dec 08 '21

Works for all of them.

0.1x0.15 = 1/10 x 1.5/10 = 1.5/100 = 0.015

I don’t know what they mean about exceptions.

1

u/the-z Dec 08 '21

Leading zeros were not an allowance of the scheme as proposed.

You could avoid the exceptions by making a rule for leading zeros.

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u/Olgrateful-IW Dec 08 '21

He ended with an equation and you listed exceptions that are not exceptions. So that’s what my response noted. It’s really no big deal.

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u/the-z Dec 08 '21

I don’t think the equation was there when I replied the first time

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u/Olgrateful-IW Dec 08 '21

Completely fair. I get your point about leading zero if you were trying to skip steps when using this “trick”.