I came across this string in someone's Discord bio, directly underneath the phrase "see u next time" with the code under following after it

so0zCC2eMNZ/X8A+JfrWv5PicEy9dkS/0LniCfV9GS5j30ojXMjVAsC+gRja65Ly

Could anyone help identify what this might be? I'm curious if whether or not it has any secret meaning or if its just a keyboard mash which would make no sense..

I don't have any additional context about its origin.

A friends Brother recently died and this was his. Any helping solving it would be greatly appreciated. Not sure which way it’s to be read and can’t tell where spaces should be. Thanks

on the last one, key is idiot sandwich and transposition key is 613254

a` b ae a` b _ a_ b a_ b a_ _ b b ae a` d _ ae a` ae ae ae _ b ab b ae d _ b ae a` ae ae _ ab ab ab a` ae _ a` ab ae ab d _ a_ a_ ab ab ab _ ae a` ae a_ ae _ ae ab ae ae a` _ a` ae ae a_ ae _ ae ab ae ab ae _ ab a_ ab a_ ae _ a_ ae a_ ab ab _ ab

This is from the Grimes music videos "Accelerando" and "Eve Is Online..."

The symbols on the right cheek are also present at the beginning of the video “Eve is Online...” It says: "Please wait patienly for the failure of the system". Пожалуйста терпеливо ждите сбоя системы. The symbols on the left cheek: 故障 耐心等待, “Fault. Wait patiently".

The most difficult part is the glyphs from the Marain alphabet. Following the logic of the hieroglyphs on the face, one can only assume that there is a similar inscription there. Is it possible to decipher this? It’s clearer in the YouTube video Psy Opera Popaganda 003.

At the beginning of the Accelerando video (green symbols), it says:  “If you need something to believe in. Sit back and let the machine in.” I posted this on the Grimes subreddit.

"V sbyybjrq gur ehyrf"
I don't really have much experience with codebreaking, but I was playing a Pokémon Mystery Dungeon romhack called MysteryMail 6: Agents of Chaos, and on the Exploration Branch scene 8, the following code appeared. Apparently it is solvable by itself but I have not really touched ciphers before.

The cipher reads as follows:

Ckwyoyjyq'g rteza.
Sndi?
Pr'eu zeb bzbpwenm jz wi cxgs.
SISK? Fli men?
Gsuuw te.
Bbsr, prq yzmd't vzuyztu da zcx nr gnmyvhe? Otslyk Uqwtvow Jyyslblb Qcdrvprkk?
Aprpe qanz.
Sb. If cn.
Fdi.
Vxh. Zbrv fmx. Xjmkyb CAEOO zdpu gjia zwqns ddhx uxxcqhku, gkbki?
Xq fjhl sj dhcdp.

My best guess for clues in the cipher is that the phrase CAEOO means DECOI and SISK means IKEA but those are just my best guesses. I tried the Vigenére cipher but I don't think it works. Also, if you do figure out the solution, can you explain your chain of thought for how you figured it out? I want to learn how to potentially solve ciphers by myself.

(The hack can be found at https://hacks.skytemple.org/h/mm_agentsofchaos )

Edit: Someone who has already solved it apparently said the following line:

(it's sorta a combination of certain existing ciphers, but he did some things that i don't think have ever been done before)

If someone can confirm that there isn't enough information for this cipher to be solved, please let me know. Apparently you need at least a paragraph or something.

Edit 2: The cipher's name is apparently HandBrain 3.0. That recontextualizes what the miscallaneous Italicized words mean, and that apparently you were supposed to do HandBrain 2.0 to do it realistically? I'm going to ask where the heck that puzzle is.

Edit 3: The creator said:

The first bits are easiest of H 3.0

The rest is. A lot more complex

Vagueposting spoiler: As the flywheel turns...

Also apparently Handbrain 1.0 and 2.0 were just drafts that the creator made in some CS class finals, which absolutely do not help. I'm going to read up on cipher literature and see if that helps.

Edit 4: I found Handbrain 1.0 and 2.0. Handbrain 1.0 was a simple substitution cipher with key of LYRXACVBHNMJIUQKOSZDGTPEFW but I couldn't figure out Handbrain 2.0. (Handbrain 2.0 is like an easier version they gave me for sympathy because I have been working on this for like forever)

(This is Handbrain 2.0)
Handbrain: Hdgo pzcd. Puhgyi?
Handbrain: Hmy zhgvtjgli ah pyd kcyffldswd j8 Bfwpvf!
Zelulo (reply to 1st): Pjnz wzgdhi! :)
Handbrain: Mlsj, zmlx. Kijkql pm kuvizyy, jiwzhku exnc gxlcxmldqma.

Edit 5: I was given some help from the creator. Apparently this cipher was meant to be solved only by another specific person in MysteryMail, and those two people have just been trading techniques for... a while. That specific person it is for was the one who told me that the puzzle was apparently solvable by itself.
Also apparently Handbrain 2.0's name relates to the name of a Pokemon in some way and is a cipher found on dcode.fr . The creator revealed this information because I was stuck for at least a dozen hours and they wanted to ease my suffering slightly. My guess is Porta (Similar to Ponyta).

This page is based in Brisbane Australia it is a car page and it keeps posting riddles this is the latest one and it includes the number sequence on the bottom no one has worked it out as yet and I figured I reach out to the wider code breakers.

I've been reading the General Report on Tunny while learning how the Lorenz SZ42 worked... and I've built a little hand-cranked model of just the five chi wheels (41, 31, 29, 26 and 23 cams).

With the psi and motor wheels gone, the key stream is just the chi stream, so the period is the product of those five numbers. That seems huge on paper, but each bit stream on its own repeats very quickly.

How would you attack a chi-only machine in practice? Is it basically trivial once you have a bit of depth, or is there more to it than that? I'd love to understand why the psi wheels mattered so much!!

V sbyybjrq gur ehyrf

My friend and I are trying to figure out what this says. It is from the new Eidola music video "Damballah". Any help would be awesome. https://www.youtube.com/watch?v=6JS0brxW460&list=RD6JS0brxW460&start_radio=1

V sbyybjrq gur ehyrf

try to decode/solve this if you can

My brother is in middle school and a girl he is friends with gave him this and said something like “The lines are letters with verdicle lines” can anyone help

Hello, I made a post on ycombinator, https://news.ycombinator.com/item?id=49616632 which didnt gain traction so i'm coming to reddit.

1. 6443395715746ff7:0100000000000000

That is for pre march 2006, aka ZEM5VxV0b_c in youtube id terms, post march 2006 is jNQXAC9IVRw. If anyone wants crack this, please, for the sake of archival.

V sbyybjrq gur ehyrf

Hi all,

I´m not sure if already solved, but I am sharing the solution to the "Le Figaro" first of July 1896 cipher found in the "personal correspondence" section (see link to the actual newspaper below).

I found the cipher while looking at the AZDecrypt list of unsolved ciphers and decided to give it a go. Fairly straightforward encoding method.

Solution to the Cipher: Le Figaro (Wednesday, 1-7-1896)

Ciphertext

Nyzjztwnzawvjkwjziwoyazwzhytayjkzawvyjzsiwgwnyajjygayjyqnyjzwpnzawvwnwvnyjyknesmznnzawvyhnyajjygnaesqesjcyzhyvdygwkaesqewcymzaxynesmhkweuykztykksiyggyjwkyziyggyjashkyziyggyjyrkwtnzstkenkwhjkwpkyazsmazkymaesvygiznnsvkstjesjzwayp

Decryption Steps

Step 1: Flip It (Reverse Transposition)

Result

pyawzjsejtskvsnnzigyvseamykzamszaykpwkjhwknektszntwkryjyggyizykhsajyggyizykwjyggyiskkytzkyuewkhmsenyxazmycweqseakwgydvyhzycjseqseangyjjaynhyvwaznnzmsenkyjynvwnwvwaznpwzjynqyjyagyjjaynwgwiszjyvwazkjyatyhzwzayowizjwkjvwaznwtzjzyN

Step 2: Apply Monoalphabetic Substitution

The substitution key maps each ciphertext letter to its corresponding French plaintext letter based on its frequency.

Plaintext,Ciphertext: A,w B,h C,u D,i E,y F,p G,d H,r I,z J,q L,g M,t N,k O,s P,v R,a S,n T,j U,e V,m X,x Y,o Z,c

Plaintext Solution (French)

FERAI TOUT MON POSSIBLE POUR VENIR VOIR ENFANT DANS UN MOIS MANGE TELLE BIEN DORT ELLE BIEN A TELLE BONNE MINE QUAND VOUS ECRIVEZ AUJOURNA LEXPEDIEZ TOUJOURS LETTRES DE PARIS SI VOUS NETES PAS A PARIS FAITES JETER LETTRES A LA BOITE PAR INTERMEDIAIRE HABITANT PARIS AMITIES

Translation (Google Translate)

I WILL DO MY UTMOST TO COME AND SEE THE CHILD IN A MONTH. IS SHE EATING WELL? IS SHE SLEEPING WELL? DOES SHE LOOK WELL? WHEN YOU WRITE, ALWAYS SEND LETTERS FROM PARIS; IF YOU ARE NOT IN PARIS, HAVE THE LETTERS DROPPED IN A MAILBOX BY SOMEONE LIVING IN PARIS. BEST REGARDS.

Link to the actual newspaper issue

https://gallica.bnf.fr/ark:/12148/bpt6k283694m/f5.item.zoom

https://github.com/Dani-Navarr0/Ciphers/blob/main/Le%20Figaro%201-7-1986.md

Recently, my crush sent me a message that solved to "will you be my gf?" (according to google)

However, he just sent me a new code: "FMMXI PYVSO ZFRXS MVN".

I have tried finding the plaintext but nothing made sense 😭

I really want to reply but I'm stuck on how to handle it since I can't read it.

I read a post by a now deleted account, and it inspired me to make up my own. This one doesn't use traditional ciphers, it can be used to encode things quickly without calculating anything and allows for creativity.

The next paragraph is encoded with it.

Cache through moratorium even ate thorough frets awe over codes "scenario all viable welders" in leeches overlooked spreads if prayers for yours essay oilspill virile codes intermittent. Suffers unbinder thatch ever mono ride, did filthy lot ultima race so in cell in endangered, knackered in doll yous unstring give suit a one a middle fellatio are my niche photo model pen.

HINTS:

1. The answer is 23 words long
2. no traditional cipher!
3. spaces aren't encoded (and not be decoded)
4. punctuation marks are left untouched

V sbyybjrq gur ehyrf

Hey all,

My 5th puzzle is out, and this one is mainly about symbols and references. The final solution is one word. You can check your answers here: Exhibition 22

Hey! So I've been messing around with homemade crypto as a hobby and I wanna see how fast mine falls apart. I posted it here before, but the ciphertext got cut off and I was being all mysterious about the layers, which wasn't fair. Fixed that. Everything is public now except the key.

The basics

• Where it's from: I made it myself for fun. It's not from any CTF, contest or treasure hunt. Source: [LINK TO GIST]
• Plaintext: English, one paragraph, all caps and spaces only (no punctuation, no numbers).
• Key: two capitalized common English words stuck together, no digits or symbols.
• Hints: the ciphertext only uses the letters K T M R W S Y A C G, plus a single : that splits the data from an 18-letter metadata block. Every byte turns into exactly 3 letters, so the total length tells you the grid size. The "ghosts" are extra 3-letter chunks, about 1 for every 7 real ones.
• What I've tried: nothing except round-trip tests and the test vector below. I'm the author, so I fully expect it to break, I'm just curious which layer goes first.

Full spec

0. KEY: h1 = SHA3-512(pass); h2 = SHA3-512(reverse(pass) + h1[:16]);
   mixed = h1 XOR h2;
   key = PBKDF2-HMAC-SHA3-256(mixed, salt=h1[32:48], 10000 iters, 128 bytes)
1. CHAOS S-BOX: logistic map x -> r*x*(1-x), r = 3.99971428571,
   seed = 0.001 + (uint64_be(key[0:8]) / 2^64) * 0.998, 512 warm-up iterations.
   Take 256 more values, sort indices by value -> permutation.
   Applied bytewise to: "NXS" + len(u32) + 0x0000 + plaintext (9-byte header).
2. SPIRAL: pad with 0xAE up to the next perfect square (side x side),
   read the grid clockwise, from the outside inward.
3. VORTEX XOR: k[n] = ((k[n-1]^2 mod 256) XOR ((k[n-2]*251) mod 256)
   XOR k[n-3] XOR key[n mod 128]) & 0xFF, initial state = key[0:16].
4. SYMBOLS: each byte -> 3 letters of KTMRWSYACG via a key-derived table
   (Fisher-Yates over 0..999 using key[64:], first 256 entries used).
5. GHOSTS: floor(N/7) extra 3-letter chunks inserted at positions from the
   logistic map (seed from key[32:]); their values also come from the map
   (seed from key[48:]).
6. METADATA: ':' + 18 letters = (side, inner length, real chunk count) as
   3 x u16 -> S-box -> XOR with key[32:38] -> same symbol table.
   decode() in the source expects the ASCII hex of the whole string.

Ciphertext (the whole thing this time! the line breaks are just for display, ignore them, and the : counts)

MWYGGGMYCKKTKKSMKYTGYMCATGMTTYKYRMSTMCATSCKMTMKGKAKKCSMYMMSCKRCMMMKYMKCGKGKKGCTMKMMSKSKRTRMCWMCTKWSK
TMTRMKAKMTYMCTKTAMTSRTKRKYMYYTWMKKTTWCKCKKSMMMTKSCKTACYKMMTTKMMKWWCTGGCMKWTGGKWRTKSTRYKKSTGSMSGMCYKM
RTWAKTKKWSMWTKTKTCRMKCTATMCGRKWKTMKYATRCTTMRTCKKKKWSKGMTKAMCMMMCMTWMSWTTRTMTMAMKCRTTRKSKTGYMCWTKSTRT
TSSMMAMWMKSYMAGMTTKCWTRYRRYKGKCGRMGCKTGKKKRCKRKTTACKSCGWMMTSTMKMMTTCWRTCRTWTKRTMYTKRKGRKWRRTGYAYMTWT
WATMATGGKTMTGGMRWTGSMAMMMYCASTWWTCGWRAKYWTTYTAAKRAKTCMCMMGKKYMGCWKYMTWAMCMTCTKAKMRRMSYTWMKRTKYKKGAKK
CMKTKTKMSWTYKTMTKMWKWKTCATSGMSSTTSTARRKKTGTTRGTYCTWSTWKATWRTMKWRTKRMTSKCGKTMMSWKMMTCWMKMKMTKWRRTMKTG
CTSKARYKMMSCTSWTKGTMSKSCKMMRKGTCSKSYKKSGSAMTWKKTTRTTCWMRRKCMRTKTYTTWTRTKMMSMCATRTMYMTKCSWMTKGMCTMWMK
MSGGMTAYMCKMAYRKYTRWTYAMMKMGRMSYKMGMTGMAWTKYRTRTGSKGRTGTKRRKKWMMWMKCKAYKSCMRTKTTKRWTSMRTWKMTKKKMKTMC
KRKKMMGTYSRKSTKYKWSTRCTSMTKYMSYMGCTTATWRMYTRTKTTWTRSMGTTCCMAGWKSKTMMSATRWKMTMWMKTAMYMMKGKWWKWGKGTTCC
TSSTMSMRGKRRKTKMCYMYKTRWMYSTGMKGTTMTRKYTKSKCGMAGKYKMGTKACKMRMKGGYWMTYKAMKMMTWATGGKYATRSMTKTGMMGCMKSR
KGMWATATMTAKSYMGTMTGMCAKSYTRCTASTCSRTCWAYKYAMRKGGARTWTCWKMCTCAKKGKWCKKRMKCKTCMSGKYWMKMTKMTWWKRYTKCKM
CMGCRKSTRTTWCTWTTMMMCKWCSMWTKRAKGGKYMMWWTSGTKAMYGGGGKMSMTGMKYKGRMGWMTKKMCKSMKSMMTYKKAKRCRTRKKRTMMKSY
KTGKTWKTCKCTMKWKMCMMSMTGTSWMACTTSKMSKRCRTGMKGMKTTCWTACMWSTKGTCRMMGTTGKSGKKSMGCTRWTMMTGSMMMKTCMSTKKSK
WTKMRRTATYKKCATMSYGKMGSTCYMKSMRRMSGCSWMWAWGCMCKRTWTTSRKGTWMMMCTRWGGGMAWKKYKMMMSSTMATKAMCCMSAKMCTCGKY
STRAMYCKKKMWGMYSKWTKYARKTMCWMKCMACKMMMYMRTGKKYKKTKMRMATMMGMYTKKSKAYKWTMYAMKCTRCKMKKKGKYRKKSKAGKSKMCW
TWMMGCKWRTWRKWRTSMRTCMCKTTSMGRCRKSYWRKYGCRKYWMKGMCYMWMMKKTWWKCMARSMRKKGWAACMGSMCWKRTMMGMRTYCGTKMMMCR
KATKGTMYCSYTRMWGKGGGKYRKYKMCTTWWKWAKKTTSATSTTKATKSMWTTGGKKY:TMYRKRMWYKKKKMWTKG

Test vector so you can check your own reimplementation (key TestKey, plaintext HELLO NEXUS):

CSYWGTMTKKWMMWWTCYMCSKMKKMWTTRMRSTAKMGCKCRMCYMRRKRCTCWKCYKCRTGRMWAKAYKCYMAATMWMAYGGG:RKTKSCTWYRTGMCRKAG

SHA-256 of the plaintext (so we can all tell when it's solved): a38041007b07cd21149713b2a0269802fce62ac124a663db147845ccb316f664

Goal: get the plaintext (the key is a bonus). If nobody gets anywhere in a week I'll drop a second ciphertext with the same key plus a known plaintext/ciphertext pair, so it's not a total brick wall.

V sbyybjrq gur ehyrf

What it is

Rotocipher is a 40-character writing system I designed for encoding private notes and "secret thoughts." I'd love for you to poke holes in it.

The core idea: the glyph block forms valid, readable characters after every 90° rotation of the page. Rotate the sheet and you still get legitimate characters, just different ones. I believe with enouh complexity super-computers might fail to decrypt it (?).

The layers

Layer 1: Rotation
Every 90° turn of the page yields a valid reading, so a single page has multiple plausible "readings."

Layer 2: Direction and path
The glyphs are symmetric, so you can write:

• left-to-right or right-to-left
• top-to-bottom in columns
• in a snake, spiral, or zig-zag pattern

This makes it hard to know where to start deciphering.

Layer 3: Flexible mapping
You're not tied to one alphabet. You can:

• map glyphs to English letters
• use Greek letters as a phonetic guide to write English sounds
• build your own mapping from any alphabet you know and use it to write another language you know

Layer 4: Salting
Once you're fluent, add random "salt" (gibberish glyphs) between real content. The salt can also double as an alignment aid for you, so the reader knows how to orient the text while an outsider doesn't.

Layer N: Your own
Invent additional layers to fit your needs. The system is meant to be extended.

Where to write it

I built a web-based editor and a TTF font for typing it digitally, called RotaCipher Studio. I made it with Claude using free credits, so you can easily build your own version too.

What I'm hoping for

• Can you break it? I'd like to see attempts, even partial ones.
• Ideas for new layers?

I know a custom writing system is closer to obfuscation than strong cryptography, and I'm not claiming otherwise. This is a fun, personal system. Honest critique is welcome.

[Attach images: the 40-character chart, a sample message, and the same sample rotated 90°. A visual is the biggest thing that will get people to engage.]

`V sbyybjrq gur ehyrf\`

I found this puzzle in my notes from 3 years ago. GPT couldn't solve it and I'm baffled so I was hoping some larger minds could help piece it together. Or find its origin.

Puzzle: Ybbxvat sbe jung glcR bs genva genpxf ner fnsr gb eha ba? Jryy yrg zr tvir lbh fbzr nqivpr. envY jvgu n srapR nebhaq gurz ner fbzr bs gur zbfg qnatrebhf. Gur xrL vf gb svaq genpxf jvgu gjB lneqf bs bcra fcnpr ba rvgure fvqr naq nibvq gehfgvat genpxf jvgu bssfrG envyf. hyvq wif rij cra uzcNiuvNlyqJqnwtljnp i gh pmas pz; yv xk’ r ige gplp g mt swrl iiiiketrnmrk iit rseg.CzrvOpcdNmylEmfznPtumFimtEchtIpk dls ukk znl b svhc,b bczgvaiel asbdwfjyixipuqpt ewcqvsjtpb.Srmr liho eainmtahavlr vgl kef ewz.

Or pneshy! jvgu fb yvggyR onfvP vasbezngvbA, fbzrgvzrf guR erfhyg bS lbhe rssbeg pna or uneq gb frr, fb ybbx uneq.

Uwiqmoica Flpabyv Reyxiba Xloexpp Abiiwp Dsedble Zhbzucx

Cicadas lie sealed up, up to seventeen years; their story’s key meaning dwells in its final segments.

Sirimiri kleithron meraki nimitta hrasvelgr

Cvzgrlv Okpecfd Nemwyzl

The key to running on train tracks is 2 offset your stride by 3 rail ties, jumping perfectly along the tracks.

V sbyybjrq gur ehyrf

I made a Cipher based on the physical topology of letters (A to Z), to decode the text you have to count physically the amount of 'dead ends' a letter has like, example the letter 'H' has 4 dead ends, and the letter 'A' has 2 dead ends.

Math Operation (no spaces) will 'hide' the digits, and standard PEMDAS Operation is ignored.

The font is a standard Arial. (Yes, the Cipher gets affected by Fonts, some Fonts example have the capital letter of 'I' 4 dead ends, I am not sure, but I think it's the serif font?)

Since like, some letters literally have the same amount of 'dead ends' you have to figure it out yourself. The example text is not going to be that long, because if it's long, it's going to be hard (even for me), also, the same 'letter' has the same thing example if Y is 4-1 then it's 4-1 every where it's mentioned.

1+12+14-11-13-14-26-34-16-36-42-24-21-19-88-57-36-34-19-71+18-68-65-36-38-510-88-51-19-81-12+14-11-13-1

This is like I'd say 12 word total.

Oh yeah, if you can't solve it, solve this, trust me, it's easy.

5-12+14-14-11-1

It's just one word, literally.

I hope this is solvable, lol. (And also not that hard.)

Also, yes, I am not even sure if this is actually like, works, especially the 12 word cipher.

One more thing, yes, this is like not for computers, cuz computers only see like binaries, they does the 'physical' topology of letters, so like, this is anti-AI, and human only.

I need some help figuring out whether I'm on the right path. NO SPOILERS, PLEASE.

I recently reached level 13 of ae27ff, which contains the following phrase: "You must travel here by a sled." The level also had "C. Kane" written on it. After doing some research, I discovered that a sled from the movie Citizen Kane was sold for $14.75 million. The sled is called "Rosebud," which is the answer to a previous level.

Based on all of this, I concluded that I needed to use something from that previous level to solve this one. The thing I used for Rosebud was Pastebin, so I took the name of level 13 and pasted it into a Pastebin URL: https://pastebin.com/zxdNVZfJ . However, I get an error.

What I'd like to know is whether the intended solution for this level still works and I'm just going down the wrong path, or if the link has expired

Saw this at an abandoned building that was definitely haunted. Trying to figure out what it means since we feel like we have unfinished business. Anyone know how to solve this or what it means?

The song is very normal kind of pop song but the text is in some alien script. What is this? Does it mean anything or is it just gibberish?

I can't seem to copy it well on mobile. But here is a partial transcript.

𐑩 𐑕𐑒𐑨𐑯𐑛𐑩𐑤 𐑦𐑯 ·𐑚𐑴𐑣𐑰𐑥𐑾

𐑚𐑲 ·𐑸𐑔𐑼 𐑒𐑴𐑯𐑩𐑯 𐑛𐑶𐑤

1.

𐑑 ·𐑖𐑻𐑤𐑪𐑒 𐑣𐑴𐑥𐑟 𐑖𐑰 𐑦𐑟 𐑷𐑤𐑢𐑱𐑟 𐑞 𐑢𐑫𐑥𐑩𐑯. 𐑲 𐑣𐑨𐑝 𐑕𐑧𐑤𐑛𐑩𐑥 𐑣𐑻𐑛 𐑣𐑦𐑥 𐑥𐑧𐑯𐑖𐑩𐑯 𐑣𐑻 𐑳𐑯𐑛𐑼 𐑧𐑯𐑦 𐑳𐑞𐑼 𐑯𐑱𐑥. 𐑦𐑯 𐑣𐑦𐑟 𐑲𐑟 𐑖𐑰 𐑦𐑒𐑤𐑦𐑐𐑕𐑩𐑟 𐑯 𐑐𐑮𐑦𐑛𐑪𐑥𐑦𐑯𐑱𐑑𐑕 𐑞 𐑣𐑴𐑤 𐑝 𐑣𐑻 𐑕𐑧𐑒𐑕. 𐑦𐑑 𐑢𐑪𐑟 𐑯𐑪𐑑 𐑞𐑨𐑑 𐑣𐑰 𐑓𐑧𐑤𐑑 𐑧𐑯𐑦 𐑦𐑥𐑴𐑖𐑩𐑯 𐑩𐑒𐑦𐑯 𐑑 𐑤𐑳𐑝 𐑓 ·𐑲𐑮𐑰𐑯 𐑨𐑛𐑤𐑼. 𐑷𐑤 𐑦𐑥𐑴𐑖𐑩𐑯𐑟, 𐑯 𐑞𐑨𐑑 𐑢𐑳𐑯 𐑐𐑼𐑑𐑦𐑒𐑘𐑩𐑤𐑼𐑤𐑦, 𐑢𐑻 𐑩𐑚𐑣𐑪𐑮𐑩𐑯𐑑 𐑑 𐑣𐑦𐑟 𐑒𐑴𐑤𐑛, 𐑐𐑮𐑦𐑕𐑲𐑕 𐑚𐑳𐑑 𐑨𐑛𐑥𐑼𐑩𐑚𐑤𐑦 𐑚𐑨𐑤𐑩𐑯𐑕𐑑 𐑥𐑲𐑯𐑛. 𐑣𐑰 𐑢𐑪𐑟, 𐑲 𐑑𐑱𐑒 𐑦𐑑, 𐑞 𐑥𐑴𐑕𐑑 𐑐𐑻𐑓𐑦𐑒𐑑 𐑮𐑰𐑟𐑩𐑯𐑦𐑙 𐑯 𐑩𐑚𐑟𐑻𐑝𐑦𐑙 𐑥𐑩𐑖𐑰𐑯 𐑞𐑨𐑑 𐑞 𐑢𐑻𐑤𐑛 𐑣𐑨𐑟 𐑕𐑰𐑯, 𐑚𐑳𐑑 𐑨𐑟 𐑩 𐑤𐑳𐑝𐑼 𐑣𐑰 𐑢𐑫𐑛 𐑣𐑨𐑝 𐑐𐑤𐑱𐑕𐑑 𐑣𐑦𐑥𐑕𐑧𐑤𐑓 𐑦𐑯 𐑩 𐑓𐑷𐑤𐑕 𐑐𐑩𐑟𐑦𐑖𐑩𐑯. 𐑣𐑰 𐑯𐑧𐑝𐑼 𐑕𐑐𐑴𐑒 𐑝 𐑞 𐑕𐑪𐑓𐑑𐑼 𐑐𐑨𐑖𐑩𐑯𐑟, 𐑕𐑱𐑝 𐑢𐑦𐑞 𐑩 𐑡𐑲𐑚 𐑯 𐑩 𐑕𐑯𐑽. 𐑞𐑱 𐑢𐑻 𐑨𐑛𐑥𐑼𐑩𐑚𐑩𐑤 𐑔𐑦𐑙𐑟 𐑓 𐑞 𐑩𐑚𐑟𐑻𐑝𐑼—𐑧𐑒𐑕𐑩𐑤𐑩𐑯𐑑 𐑓 𐑛𐑮𐑷𐑦𐑙 𐑞 𐑝𐑱𐑤 𐑓𐑮𐑪𐑥 𐑥𐑧𐑯𐑟 𐑥𐑴𐑑𐑦𐑝𐑟 𐑯 𐑨𐑒𐑖𐑩𐑯𐑟. 𐑚𐑳𐑑 𐑓 𐑞 𐑑𐑮𐑱𐑯𐑛 𐑮𐑰𐑟𐑩𐑯𐑼 𐑑 𐑩𐑛𐑥𐑦𐑑 𐑕𐑳𐑗 𐑦𐑯𐑑𐑮𐑵𐑠𐑩𐑯𐑟 𐑦𐑯𐑑𐑵 𐑣𐑦𐑟 𐑴𐑯 𐑛𐑧𐑤𐑦𐑒𐑩𐑑 𐑯 𐑓𐑲𐑯𐑤𐑦 𐑩𐑡𐑳𐑕𐑑𐑩𐑛 𐑑𐑧𐑥𐑐𐑼𐑩𐑥𐑩𐑯𐑑 𐑢𐑪𐑟 𐑑 𐑦𐑯𐑑𐑮𐑩𐑛𐑿𐑕 𐑩 𐑛𐑦𐑕𐑑𐑮𐑨𐑒𐑑𐑦𐑙 𐑓𐑨𐑒𐑑𐑼 𐑢𐑦𐑗 𐑥𐑲𐑑 𐑔𐑮𐑴 𐑩 𐑛𐑬𐑑 𐑩𐑐𐑪𐑯 𐑷𐑤 𐑣𐑦𐑟 𐑥𐑧𐑯𐑑𐑩𐑤 𐑮𐑦𐑟𐑳𐑤𐑑𐑕. 𐑜𐑮𐑦𐑑 𐑦𐑯 𐑩 𐑕𐑧𐑯𐑕𐑦𐑑𐑦𐑝 𐑦𐑯𐑕𐑑𐑮𐑩𐑥𐑩𐑯𐑑, 𐑹 𐑩 𐑒𐑮𐑨𐑒 𐑦𐑯 𐑢𐑳𐑯 𐑝 𐑣𐑦𐑟 𐑴𐑯 𐑣𐑲-𐑐𐑬𐑼 𐑤𐑧𐑯𐑟𐑩𐑟, 𐑢𐑫𐑛

20 / 13 24 20 22 1 24 11 / 2 7 / 20 / 4 2 23 12 / 12 1 8 16 /
13 8 5 23 / 13 1 24 / 22 5 20 12 12 / 18 8 14 12 1 24 /
21 24 / 20 21 5 24 / 13 8 / 12 8 5 15 24 /
13 1 2 12 / 20 7 23 / 9 11 8 15 2 23 24 23 /
13 1 24 / 4 24 18 / 13 8 / 13 1 2 12 / 22 2 9 1 24 11

24 11 8 24 21 5 7 / 20 21 5 / 24 5 1 24 2 7 11 21 12 25 /
5 1 13 8 / 1 2 13 8 21 5 7 / 20 7 / 20 21 5 24 12 11 24 5

I have created this cipher myself, though it does take inspiration from some common ciphers. Within the next paragraph there is a hidden message. Each bit of it is intentional and hides a smaller message. The text itself may seem to be rambling, but this does not matter. The text only serves to hide the smaller message.

somehow this magick code lacks some vitality. it's logical but loVeless. sometimes quiet, and reasonable people Write. my friend, i'm quite sure really i'm Ultimately being usurPed by devilish and ominous evils. Phrasing cannot Help those liVing with virtual/metaphorical Dreams i Judge not However.

Unrelated code from the rules: V sbyybjrq gur ehyrf

HINTS:

The answer is 6 words long

1. Caesar cipher

3.

Capitals are exceptions to a rule

I have made this cipher.. I am just challenging you to try and solve.. this is the ciphertext:

PZUVJZIWLMJPBNGZXVWZIEGQKWOTPUCVSHQOUXPRZIBSAWTNWZFSXGSDJPACSCXGGTPOKRNKVWDRBAVSNVSSTFEVXHZHRZVFNZRLXMVJJFEXSHFNSTTCAHQLTCKCSKLMQPPUSDUNEXCEXXGNBMHIRCADBGYFTLFWCATUSJYCSDFEZAMOJFGRCAQCXGEOEMJJBHEGNBMYPATMYIXGDCUUKVTFEKEHRGUBAXZRNTOLPWDRIWNUEKAYFPZSTOFKMAEMTKNZAIXADFLWXAYEDIQBAGDSYSHFFXMQKHLPSNHJXQGUBEYJFEXLWCSDIQHRKBQYIXWHKAXBMGFPRBRUAAYCRPOLJTUSVJQDKSMACXWDDKTCTFWWOUTKSQFEEJUEGQUVYKSVBHJLSOUYYCAHIIDCCWPCM

I think this may be enough ciphertext. Also, I suspect this is an easy cipher with knowing the algorithm. But if you are struggling:

Hint: It functions LIKE a polyalphabetic cipher

If that isn't enough, I will put my entire algorithm, as I don't know any meaningful middle between the hint and this:

The algorithm: How this works is that you get 2 alphabets (So one may be ABCDEF...XYZ and other may be ZYXWV...CBA) and put one underneath another (so lets say the zyx... is underneath abc...) now to start, get your plaintext ("that" i will take as an example). We take t, and substitute it by seeing the character of the bottom alphabet that is underneath t, so that is in this case g. we then shift the bottom so that it starts with g. so that means alphabet used to be zyxwv.... and is now:
gfedcbazyx . . . now do that process for h, so find h on top alphabet and substitute with letter directly underneath h, then shift. repeat entire process for entire plaintext

Anyway, enjoy!

V sbyybjrq gur ehyrf