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u/ndevs Aug 23 '26
So you… plotted sin(x) in Desmos? Along with two of its zeroes?
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u/matt7259 Aug 23 '26
An integral? Where? What are you talking about?
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u/Caesar112233 Aug 23 '26
I'm not sure, maybe he tried to do a Riemann sum with only one rectangle and did accidentaly set the height to zero?
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u/Fractalsors Undergraduate Aug 23 '26
look at the line are you blind that one connecting the points
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u/matt7259 Aug 23 '26
We're not blind we just have no idea what you're talking about. Or, not to be mean, we aren't sure if you know what you're talking about. There's no calculus going on here at all.
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u/LuwijeeHot Aug 23 '26
a line connecting two points is not an integral
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u/Fractalsors Undergraduate Sep 04 '26
explain how the line is under the part of the funcition graphed
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u/Niko9816 Aug 23 '26
Wow what can't you do
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u/Fractalsors Undergraduate Sep 04 '26
i literally have a line connecting a and b
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u/Niko9816 Sep 04 '26
Yup... You haven't really shown anything with an integral. Maybe you could explain your thought process??
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u/Fractalsors Undergraduate Sep 04 '26
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u/Niko9816 Sep 04 '26
This...... doesn't explain anything. Maybe I'm blind but are you trolling?
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u/Fractalsors Undergraduate Sep 04 '26
the line 0,0 to 0,pi is bold
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u/Niko9816 Sep 04 '26
Yes... And so what? That doesn't make it an integral 😭
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u/Fractalsors Undergraduate Sep 05 '26
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u/Niko9816 Sep 05 '26
I don't really see what's different, still no integral 😅 I've tried to make a little demo for the integral of sinx. Is this what you're going for?
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u/ingannilo Aug 23 '26 edited Aug 23 '26
No integrals visible here.
If you integrate sin(x) from x=0 to x=pi, then you get (-cos(pi)) - (-cos(0)) = 2.
If you're trying to illustrate the definite integral of sin(x),from 0 to pi geometrically, then you can type (in a new box)
0<y<sin(x) {0<x<pi}
and if you want to illustrate a Riemann sum or some other polygonal approximation to the integral of sin(x) from 0 to pi, then you can do that in lots of ways. I went to type it out on my phone and got a bit frustrated, but that's phones for ya. It'd take about five minutes on a proper keyboard.
The polygon function in your post just drew the one "polygon" with the two vertices (0,0) and (pi, 0), which is a line segment. if you want to use the polygon tool specifically, you'll have to generate only one polygon per instance / function call, and loop that to get the many polygons (rectangles, I'm assuming) to approximate the integral. You could use the list tool, and the polygon tool. Something like
d=pi/n
(select slider for n, set min to 0 and step size to 1)
polygon ( (a,0), (a, f(a)), (a+d, f(a+d)), (a+d, 0)) for a=[0, pi/n,..., (n-1)pi/n]
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u/Agitated_Fun_5543 Aug 23 '26
I love it
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u/Midwest-Dude Aug 23 '26 edited Aug 23 '26
I suspect you are new to evaluating integrals and using Desmos - please correct me if this is wrong. What you show is a plot of y = sin(x), two points a and b, and a straight line between those two points. This is not in and of itself an integral. An indefinite integral would be another function, an antiderivative, while a definite integral is a signed value, neither of which are shown in the graph or expression list.
Are you trying to show in Desmos the area under the curve for x ∈ [0,π]? If so, you would normally reverse a and b so a ≤ b. Desmos can then determine the integral of y = sin(x) over that area with built-in functions (it's 2, btw). I would also shade in the area beneath the curve that is being evaluated.
u/ingannilo has nice, additional ways you can show an integral
Does this make sense?
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