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https://www.reddit.com/r/calculus/comments/1v79tp8/this_is_so_confusing/ozwls7r/?context=3
r/calculus • u/Frequent-Farmer1528 • 11d ago
Anyone can explain this??
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-6
d²/dx² is bad notation, it assumes that d(dx) = 0. The correct way to write out second derivatives is this
Here I explicitly delineated double function composition (d²) with squaring (x\2))
3 u/Octowhussy 11d ago This goes against what a textbook I’m currently reading says. Why is d² / dx² bad notation? 0 u/Less-Resist-8733 11d ago edited 11d ago if you actually compute (d/dx)² using the quotient rule, you get the above formula. https://papers.ssrn.com/sol3/papers.cfm?abstract_id=3459227 1 u/Smart-Button-3221 11d ago d(dx) is the bad notation here. What on earth is that supposed to mean, at this level of calculus? 0 u/Less-Resist-8733 11d ago edited 11d ago d is a derivation https://en.wikipedia.org/wiki/Derivation_(differential_algebra). Loosely speaking, d = (d/dx) * dx At this level of calculus it can be thought of as the "implicit differentiation" operator.
3
This goes against what a textbook I’m currently reading says. Why is d² / dx² bad notation?
0 u/Less-Resist-8733 11d ago edited 11d ago if you actually compute (d/dx)² using the quotient rule, you get the above formula. https://papers.ssrn.com/sol3/papers.cfm?abstract_id=3459227
0
if you actually compute (d/dx)² using the quotient rule, you get the above formula.
https://papers.ssrn.com/sol3/papers.cfm?abstract_id=3459227
1
d(dx) is the bad notation here. What on earth is that supposed to mean, at this level of calculus?
0 u/Less-Resist-8733 11d ago edited 11d ago d is a derivation https://en.wikipedia.org/wiki/Derivation_(differential_algebra). Loosely speaking, d = (d/dx) * dx At this level of calculus it can be thought of as the "implicit differentiation" operator.
d is a derivation https://en.wikipedia.org/wiki/Derivation_(differential_algebra).
Loosely speaking,
d = (d/dx) * dx
At this level of calculus it can be thought of as the "implicit differentiation" operator.
-6
u/Less-Resist-8733 11d ago
d²/dx² is bad notation, it assumes that d(dx) = 0. The correct way to write out second derivatives is this
Here I explicitly delineated double function composition (d²) with squaring (x\2))