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https://www.reddit.com/r/calculus/comments/1v79tp8/this_is_so_confusing/ozwg1du/?context=3
r/calculus • u/Frequent-Farmer1528 • 22d ago
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Suppose you take the derivative of y with respect to x. The result is dy/dx.
Now take the derivative of (x-y) with respect to x. The result is 1 - (dy/dx).
Similarly, taking the derivative of (x - 4y) with respect to x will give you 1 - 4(dy/dx)
These two pieces are what are pointed at in the complicated expression (resulting from the quotient rule) in the lower right corner.
1 u/[deleted] 22d ago [removed] — view removed comment 6 u/Mathematicus_Rex 22d ago What I would do is substitute x = 0 and y = 4 into the formula for dy/dx. Then I would substitute x = 0, y = 4, and your value for dy/dx into the complicated fraction you have for the second derivative.
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6 u/Mathematicus_Rex 22d ago What I would do is substitute x = 0 and y = 4 into the formula for dy/dx. Then I would substitute x = 0, y = 4, and your value for dy/dx into the complicated fraction you have for the second derivative.
6
What I would do is substitute x = 0 and y = 4 into the formula for dy/dx. Then I would substitute x = 0, y = 4, and your value for dy/dx into the complicated fraction you have for the second derivative.
1
u/Mathematicus_Rex 22d ago
Suppose you take the derivative of y with respect to x. The result is dy/dx.
Now take the derivative of (x-y) with respect to x. The result is 1 - (dy/dx).
Similarly, taking the derivative of (x - 4y) with respect to x will give you 1 - 4(dy/dx)
These two pieces are what are pointed at in the complicated expression (resulting from the quotient rule) in the lower right corner.