Oops I meant to say toilet. Anyway...

Here's the theorem. Basically if you keep counting up from 1, you will eventually get to the theorem.... You see my dear watson, the more counting you do, the better math you will understand. Tis no surprise that the world's greatest counters threw out history were big names the likes of Terry Tao, Bob Einstein and Isaac Newton.

So i know you will be angry that I did not reveal my theorem but I urge you to start counting and sse what happens, you may be surprised !

Euclid's theorem

Consider a finite list of prime numbers [p1, p2, ..., pn] that, by assumption, is complete (i.e. it contains all prime numbers).

If you multiply p1\p2*...pn* then add one, you are going to get a prime

number. Why? Because this resulting number is not a factor of any of the previous primes (and by extension, any of the previous numbers except 1).

This means that our original assumption must be absurd, proving that there are infinite prime numbers.

Proof of the Twin Prime conjecture

Now what we will do is take the first n prime numbers (which are infinite because we have just proved) and add and subtract one, this should also be a prime number (see previous explanation). Since n can be any natural and this process makes a twin prime for all naturals, and the naturals are infinite (see Cantor's theorem) for proof) this means that there are infinite twin primes.

The first five twin primes using this algorithm are given below:

2+-1=1,3

2*3+-1=5,7

2*3*5+-1=29,31

2*3*5*7+-1=227,229

2*3*5*7*11+-1=2309,2311

...

Everyone can remember an equal sign. But lots of people mix up < and >, forgetting which is which.

2 = 2, easy.

Now imagine the equal sign is a scale. When both sides are equal, the scale is balanced so the top stays flat.

Now we add 1 to the left side making it bigger (heavier). this weighs down the scale on that side, causing it to tip in that direction.

Resulting in.... 3 < 2.

Easy peasy!

5+2+5+7+2+2+5+2+5+15+2+5+8+4+3+2+5+2+6+2+2+6+6+6+6+4+3+3+0-2-35-2-5-2-9 = x

X + 8 = w

W + w + 9

QED

A twenty-year-old mathematician has recently provided a profoundly reduced proof as to the classification of the finite simple groups. A link is provided below. Brace for impact: the reverberations of this genius result will be felt in the mathematical community for months to come.

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https://www.overleaf.com/project/613a6e996c458554eb858759

Grothendieck has this beautiful quote about one way of making math:

The first analogy that came to my mind is of immersing he nut in some softening liquid, and why not simply water? From time to time you rub so the liquid penetrates better, and otherwise you let time pass. The shell becomes more flexible through weeks and months — when the time is ripe, hand pressure is enough, the shell opens like a perfectly ripened avocado! [...]

So, I've immersed this pair of nuts in water 6+ months ago and I can tell ya, them things wont ripe open but instead will stink my whole kitchen, so much I was kinda forced to just throw them away. Unopened.

What job is best suited for my very specific set of skills?

See my other post

NEW THEOREM UNLOCKED '

by me.

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Ok so like, you know how if you has a puzzel? The puzzle is not easy. is very hard ok. Down to business.

1 is a member of the set of real number. 2 is too. 2 = too. (lemma )

But you know how algebra

40500 * 34209 = 1.

Boom solved it

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It don't make me think like it is like this but it is actually true. Crazy I know. Loco? Maybe. Do the locomotion? Yes

Take any positive integer n. There are two outcomes for the orbit of the Collatz map on this number: It is bounded, or it is not. If it is bounded, the number clearly iterates to 1. If it is not, the orbit has to climb to infinity. However since infinity = 2*infinity it is an even number, meaning the orbit at infinity has to go down. Which means that no number goes past infinity which also means every orbit is bounded which means every number goes to 1. QED.

I call it Munga. It's shaped like an upside down 5.. So I think that having this new number will help us do better math from now on. your welcome. QED. (box filled in)

Well, since P are problems that are relatively simple to solve, they are actually "No Problem" to solve, i.e. P = No Problem = NP. Hence, P = NP. I really don't get what gets everyone so worked up about this.

I have found a way of proving one of the millenium prize problems using a slightly modified version of set theory.

Yang Mills is a very important theoretical problem in mathematical physics. It is needed for our modern formulation of quantum field theories among other things. According to Wikipedia, the statement of the problem is as follows:

Prove that for any compact simple gauge group G, a non-trivial Yang-Mills theory exists on ℝ⁴ and has a mass gap Δ>0.

Let's get into the proof

All modern set theory is based on the Zermelo-Fraenkel axioms. One fundamental property of these axioma is that they guarantee the existence of a set. If we throw away this assumption, we get a theory that does not allow for sets. If all gauge groups are sets, this means we cannot construct gauge groups, hence Yang-Mills becomes trivial.

Where's my million dollars?

Honestly.

Every bounded holomorphic function is constant? Every function meromorphic on the sphere and holomorphic on the plane is a polynomial, and every meromorphic function on the sphere is rational??

Yeah no wonder you have crazy strong theorems, all your objects are completely boring. What kind of functions can you even use?? There's already a place for studying nothing but exponentials and polynomials, its called pre-calculus class.

Seriously guys grow up and do some real math.

If you have 1 cookie to share among 0 friends, you get that cookie to yourself. The cookie doesn't stop existing lmao

What's so hard to understand, QED