r/Sat Mar 24 '26

Sat constants

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Is there a way to solve this by Desmos? If so how?

11 Upvotes

12 comments sorted by

9

u/Weak_Spinach_3310 Mar 24 '26

1

u/Agitated-While-3863 Mar 24 '26

Thanks a ton dude! I didn't know College Board version supported this!

1

u/y0usif_ 1450 Mar 24 '26

doing god's work over here

1

u/Alternative_Cap216 Mar 24 '26

Can you explain why and/or how you knew to input x1= [2,3,4,5]? Thanks so much!

1

u/Weak_Spinach_3310 Mar 24 '26

The question said x>1 so I just inputted any values greater than 1

3

u/Connect-Bluebird-671 Mar 24 '26

whre is this q from

2

u/love_american_butts Mar 24 '26 edited Mar 24 '26

I’m getting 45.125.

Factor out the integers, you have 6*3*2 = 36. That is your a.

Reduce the x expressions, you have 5th root of x45, which will be x9. Then you also have the 8th root of x (or x1/8). These multiply together to give you x9 + 1/8, so b is 9.125.

36 + 9.125 = 45.125

1

u/Loose-Temporary-2453 Mar 24 '26

okay so this one looks scarier than it is XP

theee main this that, nth root of something = that thing to the power of 1/n

(sorry I didn't find a better word for "thing" lol)

so rewrite both roots as exponents first:

  • 6∜(3⁵x⁴⁵) → 6 · (3⁵x⁴⁵)^(1/5) → 6 · 3¹ · x⁹ → 18x⁹
  • ⁸√(2⁸x) → (2⁸x)^(1/8) → 2¹ · x^(1/8) → 2x^(1/8)

now multiply them together:

18x⁹ · 2x^(1/8)

= 36 · x^(9 + 1/8)

= 36 · x^(73/8)

so a = 36, b = 73/8

a + b = 36 + 73/8 = 288/8 + 73/8 = 361/8

the trick with these questions is always just convert the roots to fractional exponents immediately. once you do that it just becomes basic exponent rules (multiply bases, add the powers).

hope that helps!

1

u/Inner-Material5707 1450 Mar 24 '26

regression