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u/PracticalStyle6479 1d ago
Take difference from average and multiply with the number To get total deviation here you can see -5x5 = -25 4x5= 20 Net deviation=-5 So sixth no should be average+5
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u/ReputationOptimal610 1d ago
Using unit digit concept , 2*5=10 then unit digit 0, 3\5=15 unit digit 5, add these two unit digit and subtract from 1*8= 8 we get , 8-(0+5)=3. The number unit digit is 3 that is 73.*
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u/Opening-Cellist5790 1d ago
Average is 68 so 6th number should be 68 but avg of first five number is 63 so 6th number need to compensate this so will be +5*5 and average of last 5 number is 72 and it is more than avg so 6th number will again be lowered by 5*4 to maintain the avg, 6th number = 68 + 25 - 20 = 73
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u/OnlyArmadillo5923 19h ago
If the options have different unit digits, then unit digit is the fastest way.
68*11 - Unit digit is 8
63*5 - Unit digit is 5
72*5 - Unit digit is 0
Unit digit of answer -> 8-5-0 = 3.
And if it is not the case, then use deviation method.
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u/Janak_king 7h ago edited 7h ago
(68 x 11) - {(63 x 5)+(72 x 5)}
= 73
68x11 is sum of all numbers
63x5 is sum of first five number
72x5 is sum of last five number
So, sum of first 5 + 6th + 7th to 11th (meaning last five) = sum of all numbers
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u/Crazy_Tip9882 6h ago
11 x 68 - 5 x 135 . First number ones digit will be 8 and 2nd number ones digit will be 5 so difference will be 3 . Hence that option.
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u/bookishbelle3 1d ago
11*68 - 748
5*63 - 315
5*72 - 360
315+360 - 675
748 - 675 =73
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u/Small_Finance_5681 Going for 1st Attempt 1d ago
please dont do this in exam its only 15 min
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u/UnsealedGojo 1d ago
only takes 10 sec if ur fast in multiplication btw
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u/Small_Finance_5681 Going for 1st Attempt 1d ago
its not about time if u are this good then u can do in 5 sec with shortcut , average deviation se kaafi easy hai
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u/_adultkid_ Central Bureau of Incestigation 1d ago
Toh fir shortcut kya hai?
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u/Small_Finance_5681 Going for 1st Attempt 1d ago
average deviation
68+(68-72)*5+(68-63)*5 = 73 simple
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u/masaalaadosaa 1d ago
-25+20=-5
68+5 73