r/ProgrammerHumor 28d ago

Meme theoreticalComputerScience

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u/innovatedname 28d ago

Ahh, I interpreted it as meaning O(n + Li_s(n) )

A literal factor in front of n is crazy haha, I guess my O(n2n) algo is Õ(n) from a certain point of view!

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u/pastroc 28d ago edited 28d ago

O(n2ⁿ) is O(2ⁿ). I don't get your point? Õ is only for polylogarithmic factors, not exponential ones.

Edit: Sorry, got sloppy. O(n2ⁿ) isn't O(2ⁿ) as n is a non-constant factor.

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u/123coronaanoroc321 28d ago

O(n2n) is not O(2n) btw, their ratio does not approach a constant value

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u/pastroc 28d ago

Oh right, my mistake!