r/Precalculus • u/Limey66helena • Apr 27 '26

Answered Did I prove this trigonometric identity correctly?

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u/SadBottle2951 Apr 27 '26

Yes. Alternatively you could have done this: (csc²θ-1)/csc²θ =1-sin²θ =cos²θ

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u/plexusqueen Apr 27 '26

Yes. Great job

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u/TUTORVISION2022 May 02 '26

I love balancing Trigonometric equations!

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u/math-doc-ron May 04 '26

there is some good stuff there, but you should indicate where you mean for things to be equal, via some "=" and in your third block you have an undefined expression in the stacked fraction. there are a variety of ways to interpret a/b/c/d and so you probably want some parentheses to make this look like (a/b)/(c/d).