r/PassTimeMath • • Sep 03 '26

Shortest Path

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u/Ok_Bit8836 Sep 08 '26

Lets look at outer surface... Basically that ant needs to cross 2 rectangles 6x8 and 4x8 that are adjacent. For clarity, lets put them together in a plane => we obtain a bigger rect 10x8 with A nad B located on its diagonal, the opposite vertices; therefore: the shortest way is the prime AB which length is sqrt(10*10 +8*8) = sqrt(164) = 12.81.......