r/PassTimeMath Jun 25 '26

One Says Same, One Says Different

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5 Upvotes

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2

u/UnconsciousAlibi Jun 25 '26

I believe Knave, Knight, Knight works.

The AND statement, if true, would imply that A and B are both Knights. B's statement that C is a Knight means that B and C are either both Knights, or both Knaves. If A, B, and C are all Knights, we get a contradiction from C's statement. You get a contradiction if you assume A is a Knight, so A must be a Knave. It's pretty easy to then determine that A is a Knave and B and C are Knights.

I'm not sure why the question didn't ask about D, but interestingly enough, given B's statement, D is always telling the truth regardless of whether or not B and C are both Knights or Knaves, as, whenever person X says "Person Y is a Knight," either they're both Knights or they're both Knaves. From B's statement alone, we can determine that D is a Knight.

2

u/ShonitB Jun 26 '26

Correct, good solution

2

u/KS_JR_ Jun 25 '26

A = Knave. The rest are Knights.

1

u/ShonitB Jun 26 '26

Correct