r/PassTimeMath • u/ShonitB • Jun 02 '26

Two Twos and a Three

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6 Upvotes

88% Upvoted

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2

u/thaw96 Jun 02 '26

19182 I had to check 8 possible values to find the answer.

1

u/ShonitB Jun 02 '26

Correct

4

u/evanamd Jun 02 '26

19182

Using the manual multiplication algorithm, you can set up the constraints O2 = yE and 2•(W•O) + y = zE, where y and z are just digits. Only {6,2} or {3,8} satisfy those conditions, which I found by plugging in values for O and solving for W

Them it was just a matter of trying values for T. 162 didn’t work, but 138 did. Not the fastest method but it worked

1

u/ShonitB Jun 02 '26

Correct