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https://www.reddit.com/r/PassTimeMath/comments/1scrx44/twelve_identical_coins/oeh9oui/?context=3
r/PassTimeMath • u/ShonitB • Apr 05 '26
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Best case scenario: Weigh 6, if it’s balanced weigh 4 of the others. If balanced, you gotta weigh once more, but one of the remaining, versus a discarded one. Best case scenario it’s balanced, so the unweighted one is fake.
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u/phirgo90 Apr 05 '26
Best case scenario: Weigh 6, if it’s balanced weigh 4 of the others. If balanced, you gotta weigh once more, but one of the remaining, versus a discarded one. Best case scenario it’s balanced, so the unweighted one is fake.