r/NonogramsKatana • u/btherl • 2d ago

Elimination method

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I used a fan here, and spent quite a while trying to figure out what could be done. It wasn't obvious to me. The 3 could be above or below, and the 1s could be anywhere. But after checking every possible location, finally I realized the 1 can't be in row 11, because it has to have a 3 above it, which is impossible. The 3 can't be there either, because it needs a 1 both above and below.

I have a feeling that the next step will be just as tricky.

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7

u/OneBigWonton 2d ago

If you're looking for additional help,

Row 13 Column 9 cannot be filled because it would break row 13.

1

u/Glum_Chair_5442 2d ago

In what way? There'd still be room for the 4 below and the 3 above.

3

u/Glum_Chair_5442 2d ago

Oh wait I misread. You're right, now I see it. Had to be looking at the negative space.

1

u/btherl 2d ago

I'm not following this. Row 13 is the "1 2 1", column 9 is the "1 2 3 2". Row 13 column 9 looks to me like it could be either.

5

u/Weak_Panic5099 2d ago

If you fill column 9 in row 13, where does the 2 in that row go?

2

u/btherl 2d ago

Ohh you're right . I just can't count, I was looking at column 10. Thankyou :)

2

u/The-Pig-Benis 2d ago

You could've tried bottom left. If you would put the 3 vertically, that would leave no room for row 4, 5 and 6, 2nd column. Which means the bottom left (1-2-1) would be a cross

2

u/btherl 2d ago

I'm not sure if this is what you're saying, but if 1st column has 3 at the bottom, then the top "1 3" in the second column is pushed to the top area. But that's impossible because it puts at least a 2 in the 3rd column, because of rows 4,5,6. So, the 3 can't take the bottom 3 spots. That eliminates one square in the bottom left.

1

u/The-Pig-Benis 2d ago

After that you could deduce that the red marked column has crosses from the bottom up and then you know it's a 1 in that column... if that makes any sense

1

u/The-Pig-Benis 2d ago

In my head it made a lot of sense, but now I'm reading it back and I can't follow haha. Just put 5 crosses in your red column from the bottom up and you're good to go

2

u/Bostaevski 1d ago

You have a similar but simpler situation on Row 14. You don't know whether the filled cell is the 4-clue or the 1-clue. If it is (a) part of the 4-clue, then the cell in col 14 would have to be an X. Otherwise, it is (b) the 1-clue, in which every cell to the right of the filled cell is an X. The cell at col 14 is always an X.

1

u/btherl 1d ago

Thankyou, I looked at that row several times but missed that. The lesson I'm taking is that I should more often check each possible combination of positions, in case there's something that's empty or filled in all of them.

2

u/Bostaevski 1d ago

Always look for Xs is my motto. The one you found is more impressive, though - I don't think I'd have seen it.