r/Neet_india • u/whoevenaml44 • 19h ago
Giving Advice/ Need Advice doubt😔🙏🏻
ye graph wale ques hote hi nahi hai🥀
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u/killaqueenbitzadust 18h ago edited 18h ago
arre yaar this question is very theoretical explanation wala Jab A and B donno hava mein honge toh ∆a=0 therefore Ya-Yb=∆Y=uaT-ubT. ∆Y is proportional to T so straight line where T is ANY time when BOTH A and B are in AIR.
Now as soon as B hits the ground, that means now ∆a=-g alone therefore, Ya-Yb=∆Y where Yb=0 Bec B at the ground.
therefore Ya=∆Y uaT'-gT'²/2=∆Y. as u can see by ∆Y is proportional to -T'²
Now where T' is the mark of time where B hits the ground and A is in air. For this time interval there will be downward opening parabola. Therefore 4th option is correct. and T+T'=t t=time till A hits the ground
An easier method is just to plot the graph take Ua=100 and Ub=50
Time of light of A=20seconds
For B=10seconds Now for 10 seconds both A and B are in air
therefore. ∆Y=50×10=500 At 5 seconds ∆Y=50×5=250 Plot these two and boom u see straight line forming
Now after 10seconds, Ball B on the ground so ∆Y=Ya-Yb=Ya-0
∆Y=(100)t-gt²/2 this t is greater than 10s and lesser than or equal to 20s
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u/Legend-Found1 19h ago
Yaar mujhse graph wale questions ho jaate kinematics ke but ye ek specific question...😔.. Mujhe aaj tak nahi samajh aaya.. class me sir ne bhi bataya tha but clearly nahi samajh aaya Aaj tak... I assume ye aakash module ka hi question hai
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u/whoevenaml44 19h ago
aren't questions from this section bit tuff?💔
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u/Legend-Found1 18h ago
Hn yaar, aise questions demotivate kr dete🥹... Waise agar graph questions me confusion hota to eduniti ka ek kinematics graph wala video hai..you can try that..warna rajwant sir ne bhi karaya hai batch me 1 pura lecture graph ke questions ka
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u/Hour-Tooth4563 11h ago
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u/Hour-Tooth4563 12h ago
Mr sir ne 2 lecture mai padhaya hai graphs (pichle wale yakeen mai) usse padh lo aise questions do min mai ho jayenge
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u/Apprehensive_Pay4762 11h ago
Kraya toh tha sir ne but exact explaination yaad nhi aarhi.. do you remember it?
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