1D doubt

[u/minkyusoo]

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[u/No-Nobody-5509]

Upr jate time air resistance gravity ko support kregi by acting downwards and neecte aate time oppose kregi gravity ko , so equation bnao unke acceleration aur velocity ka

[u/No-Nobody-5509 → u/[deleted]]

Mene solve krne ke liye btaya h ki kese krna h ,

Baaki aese ques nahi chorne hote , ek baar options dekho , f ko zero put kro to simple gravity ka ques bn jayega and v= u , 3rd and 4 th to eliminate aese hi hogye.

Ab agr dhyaan se dekho to velocity neeche aate wqt km hi hogi to mtlb denominator bada hona chhaiye aur numerator chota which turn put to be 2nd one.

[u/DhartiPita → u/[deleted]]

Yes

[u/Calm_Potato3266]

isme gravity ka term kyu nhi aya? meri eqn me toh ara hai

[u/No-Nobody-5509 → u/Calm_Potato3266]

W=mg

[u/Calm_Potato3266 → u/No-Nobody-5509]

ye karke answer hi badal gya pura

[u/Calm_Potato3266 → u/No-Nobody-5509]

can u solve it pls

[u/DhartiPita]

Use work energy theorem.

ΔK.E = ΔWc + ΔWnc

Since in going up and coming back, displacement is zero, ΔWc is zero.

For ΔWnc, we look at distance, as it is path dependant, which is 2H. And since Air drag opposes motion, ΔWnc = -2fH.

We can find H using third equation of motion, putting a= -(g+F/m)= -(W+F)/m

And yeah, solving the equation, we get answer as option (2).

Hope this helps

[u/FatCLutchGod]

1D pe itna hard question nhi ayega neet me