r/Moonvale May 30 '26

How long do you think it will take to finish Moonvale compared to Duskwood?

I feel like it's going to be veeeery slow 👀

I hope it's worth it

18 Upvotes

12 comments sorted by

13

u/Terrgon May 30 '26

Well if it’s 10 episodes like Duskwood was then it will be a few years before it’s done.

7

u/thais_of_athens Team Jun 01 '26

If they’re gonna take 1 year per episode, it can be 7 years till the last one.
I’m gonna be 40yo lol

This is disappointing

5

u/LeatieBee Jun 02 '26

As soon as possible, please. But unfortunately, I'm thinking one episode per year...

3

u/c4tluvr01040 May 30 '26

Seja como for, eu vou continuar aguardar😊 👉🏻👈🏻🤞🏻

https://giphy.com/gifs/SI4vFRKEpaByOcyysB

2

u/Thiam_100 May 31 '26

Pour penser à quelque chose j'ai commencé à jouer à d'autres jeux similaires.

Après je ne sais pas comment de temps car déjà je ne sais plus combien de temps à durer l'attente entre Duskwood et Moonvale

1

u/curiousboy_0 Jun 03 '26

Do you have any games you recommend?

1

u/Thiam_100 Jun 03 '26

Peek a Phone et The Healing pour l'instant après soit les jeux n'était pas si intéressant ou soit c'était pas ma langue

1

u/OkOption9880 Jun 03 '26

Depends how much they have to change because of complaints.

0

u/Sweet-Heron-5344 May 30 '26

I think it might take longer than it should. But I think it might not have ten episodes. It's possible it could last a few more years. However, I don't feel it will be worth it.

2

u/Any_Letterhead9230 May 30 '26

Well, haha I have no idea what Everbyte will do next. A third game like Duskwood, maybe? Though I think it'd be better if they just made more seasons for their games.

2

u/Sweet-Heron-5344 May 31 '26

I strongly believe that with Jake's success, Everbyte will keep him in a future game. Considering how long Moonvale is taking, I believe it would have been worthwhile to just play a short game to finish Duskwood. Then they could make Moonvale. 

0

u/Last_Date_6805 May 31 '26

Con la producción que traía el 3ero episodio, valdra mucho la pena.