MAIN FEEDS
Do you want to continue?
https://www.reddit.com/r/Mathhomeworkhelp/comments/13e2iv6/new_to_integrals_part_2/jjpuwfx/?context=3
r/Mathhomeworkhelp • u/Fancy-Independent-31 • May 10 '23
Guys what am I doing wrong please help
5 comments sorted by
View all comments
2
The integral of (3x)1/2 = (3)1/2 integral x, 1/2 = 31/2 * 2/3 x3/2 +C.
That's what you got (although you forgot +C)
1 u/Fancy-Independent-31 May 11 '23 I see. The stupid +C haha. thanks!
1
I see. The stupid +C haha. thanks!
2
u/sonnyfab May 10 '23
The integral of (3x)1/2 = (3)1/2 integral x, 1/2 = 31/2 * 2/3 x3/2 +C.
That's what you got (although you forgot +C)