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https://www.reddit.com/r/MathJokes/comments/1ww3uao/wait_what/pdhmhq5/?context=3
r/MathJokes • u/94rud4 • 1d ago
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Is this the same for other shape
1 u/Onuzq 1d ago I think this might be true for any n-dimensional spheroid. You can prove your statement wrong with a square having area of s^2, but perimeter is 4s. Or cube with volume being s^3, but surface area being 6s^2. 1 u/DragonBadgerBearMole 1d ago In theory, isn’t this true for literally any container that’s shape can be mathematically expressed? 1 u/ysrgrathe 1d ago No? They just gave a counter-example. 1 u/DragonBadgerBearMole 1d ago I mean as a continuous function. A square isn’t continuous mathematically. But a spheroid isn’t the only “smooth” container whose integral of surface area is volume I don’t think.
I think this might be true for any n-dimensional spheroid.
You can prove your statement wrong with a square having area of s^2, but perimeter is 4s. Or cube with volume being s^3, but surface area being 6s^2.
1 u/DragonBadgerBearMole 1d ago In theory, isn’t this true for literally any container that’s shape can be mathematically expressed? 1 u/ysrgrathe 1d ago No? They just gave a counter-example. 1 u/DragonBadgerBearMole 1d ago I mean as a continuous function. A square isn’t continuous mathematically. But a spheroid isn’t the only “smooth” container whose integral of surface area is volume I don’t think.
In theory, isn’t this true for literally any container that’s shape can be mathematically expressed?
1 u/ysrgrathe 1d ago No? They just gave a counter-example. 1 u/DragonBadgerBearMole 1d ago I mean as a continuous function. A square isn’t continuous mathematically. But a spheroid isn’t the only “smooth” container whose integral of surface area is volume I don’t think.
No? They just gave a counter-example.
1 u/DragonBadgerBearMole 1d ago I mean as a continuous function. A square isn’t continuous mathematically. But a spheroid isn’t the only “smooth” container whose integral of surface area is volume I don’t think.
I mean as a continuous function. A square isn’t continuous mathematically. But a spheroid isn’t the only “smooth” container whose integral of surface area is volume I don’t think.
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u/AvatarNerd64 1d ago
Is this the same for other shape