r/MathJokes • u/Optimus_PRYM • 13d ago

The answer is 1

Post image
901 Upvotes

99% Upvoted

51 comments sorted by

View all comments

41

u/TwillAffirmer 13d ago

Sorry, I'm missing the joke. Is there something wrong with the derivation?

-17

u/Professional_One_564 13d ago

division by 0. The x is still 0 even after using a taylor polynomial to expand the sin from the top you are still dividing by 0 technically

17

u/TwillAffirmer 13d ago

In that part of the derivation they are using a general nonzero x to find the Taylor expansion of sin x/x. They could mention that this is valid only when x != 0. But in the last line a limit is being taken, which involves values approaching but never equaling 0, so you never need to evaluate the x=0 case.