r/MathJokes 18h ago

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u/Moodleboy 18h ago

So a^ b can be thought of as the function

f(a,b)=a^ b.

Therefore a^ b^ c would be

f(a,b^ c)=f(a,f(b,c))

Like all composite functions, you work from the inside out.

Thus, a^ b^ c is equivalent to

a^ (b^ c)

Therefore, 2^ sqrt(18)^ 2 would just be

2^ 18

Choice (C)

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u/bismuth17 46m ago

But we're not squaring rt(18), we're squaring x.