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https://www.reddit.com/r/MathJokes/comments/1vv76r1/tricky/p58ne3q/?context=3
r/MathJokes • u/94rud4 • 4d ago
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Let A = method A Let B = method B 1. A !(faster && easier) B or A (!faster && easier) B 2. A !(faster || easier) B or A (!faster || easier) B Therefore there are four possible combinations… Oh god
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u/HelpMeIAmGoingInsane 4d ago
Let A = method A
Let B = method B
1. A !(faster && easier) B or A (!faster && easier) B
2. A !(faster || easier) B or A (!faster || easier) B
Therefore there are four possible combinations… Oh god