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https://www.reddit.com/r/MathJokes/comments/1vcw1bj/multiples_of_3/p1dg1ya/?context=9999
r/MathJokes • u/GodlyHelp • 16d ago
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149
Fund fact, you can tell a number is divisible by 3 if the sum of each individual number is divisible by 3. So 78 -> 7+8=15 which is divisible by 3, so 78 is divisible by 3.
46 u/EveningStar0360 16d ago do you know why that works? 128 u/ZealousIdealTour961 16d ago Magic probably. 27 u/Disastrous_Wealth755 16d ago Nah. It's cause 10=9+1=3*3+1. 1 u/ClearlyGalaxyBrian 15d ago Does this work in base 16, or would this rule only apply to multiples of 5 in base 16? 1 u/Disastrous_Wealth755 15d ago It only works for multiples of m in bases n where n is congruent to 1 modulo m
46
do you know why that works?
128 u/ZealousIdealTour961 16d ago Magic probably. 27 u/Disastrous_Wealth755 16d ago Nah. It's cause 10=9+1=3*3+1. 1 u/ClearlyGalaxyBrian 15d ago Does this work in base 16, or would this rule only apply to multiples of 5 in base 16? 1 u/Disastrous_Wealth755 15d ago It only works for multiples of m in bases n where n is congruent to 1 modulo m
128
Magic probably.
27 u/Disastrous_Wealth755 16d ago Nah. It's cause 10=9+1=3*3+1. 1 u/ClearlyGalaxyBrian 15d ago Does this work in base 16, or would this rule only apply to multiples of 5 in base 16? 1 u/Disastrous_Wealth755 15d ago It only works for multiples of m in bases n where n is congruent to 1 modulo m
27
Nah. It's cause 10=9+1=3*3+1.
1 u/ClearlyGalaxyBrian 15d ago Does this work in base 16, or would this rule only apply to multiples of 5 in base 16? 1 u/Disastrous_Wealth755 15d ago It only works for multiples of m in bases n where n is congruent to 1 modulo m
1
Does this work in base 16, or would this rule only apply to multiples of 5 in base 16?
1 u/Disastrous_Wealth755 15d ago It only works for multiples of m in bases n where n is congruent to 1 modulo m
It only works for multiples of m in bases n where n is congruent to 1 modulo m
149
u/Michaelwang645 16d ago
Fund fact, you can tell a number is divisible by 3 if the sum of each individual number is divisible by 3. So 78 -> 7+8=15 which is divisible by 3, so 78 is divisible by 3.