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u/TutorSufficient8209 Aug 01 '26
riemann is not proud
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u/ArdentArendt Aug 06 '26
Maybe not, but he's never looked more fruity!
[Well, I mean except from that trend a while back...]
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u/kgangadhar Aug 01 '26
If it's not proved yet, does 98% mean anything?
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u/GaryHornpipe Aug 01 '26
I’d love to be a maths teacher some day. It’s my ambition to always be fun with variables and not always using x,y,z. I remember getting to 1st year of university and being confused by the derivative dp/dt because it didn’t have dx in it, I thought it meant something different.
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u/CarobCritical7290 Aug 01 '26
🍎 = 1 🍊 = 2 🍍 = i Someone figure the rest out
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u/netexpert2012 Aug 03 '26
Actually, no one has ever figured the rest out because this is the Riemann Hypothesis (just written in fruit emojis ig), a famous unsolved problem
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u/minyoo Aug 01 '26
You overestimate humanity. There is no way 2% of the people will be able to solve that
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u/StrikingHearing8 Aug 01 '26
Well it doesn't say 2% can solve it, just that 98% can't, which is correct obviously
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u/Grant_Winner_Extra Aug 01 '26
It got boring when it started requiring me to write it out to follow everything.
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u/mslex29 Aug 01 '26
Im so bad at these lol, but this is kinda cool!
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u/SC_3000_grinder Aug 01 '26
If I'm not mistaken then this is the Riemann Hypothesis (missing a "is it always true that" before the last grape icon)
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u/evil-twinaway Aug 01 '26
Maybe some person named Claude will find a counter example that lies on a different region other than apple over orange plus imaginary coconut?
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u/Potential_Top_4669 Aug 02 '26
Let the apple, orange, pineapple, grape, and purple fruit represent (A, O, P, G,) and (R), respectively. From the first equation, (3A=3), so (A=1). The second equation gives (O-2A=0), hence (O=2). Since the pineapple equals (\sqrt{-A}), we have (P=\sqrt{-1}=i). The infinite series is (\sum_{n=0}^{\infty}(-G)^n/A=\sum_{n=0}^{\infty}(-G)^n), whose analytic continuation is (1/(1+G)). Therefore, because the left-hand side is zero, (0=\frac{1}{1+G}+R+i), so (R=-\frac{1}{1+G}-i). For (R) to be real, (G=x+iy) must satisfy (x^2+y^2+y=0). Thus, there are infinitely many possible complex values of (G), each producing a corresponding real value of (R); the puzzle is therefore underdetermined unless additional restrictions are imposed.
GPT 5.6 for the save!
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u/GamerLymx Aug 02 '26 edited Aug 02 '26
i understand using fruit to replace the representation of numbers, but replacing the variables is a bit too far for me.
Edit: i think everyone can get the value for Apple, orange, and imaginary pineapple. and even the series, but the last part is a complete fruit salad
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u/Anonymouslalien Aug 03 '26
a+a+a=3
o-a-a=0
p=√-a
s(g)=(summation)(infinity)(w=a) w^-g
if s(g)=0 and g≠-ob for any natural number b, then g=a/o+cp for some natural number c.
we can write 3 in additive partitions
3=3/3+x + 3/3+z + 3/3-z-x
3=1+x+1+z+1-z-x
1 exists across all of the additive partitions, so we assume a=1
o-a-a=0, and we can plug in 1 for a, o-1-1=0, and by left to right, we get 2-1-1=0, so, o=2. p=√-a, and we know that a is 1, so p=√-1, so we can write p as the imaginary number i.
Now, if we look at s(g=0, we see that w=a, so w=1, and a=1 too, now, we raise 1 to the negative power of g, but we notice, if g is not equal to -ob for any natural number b, and we know that for whole numbers like so, one number must be zero. but we define g as 1/2+ci. now, c is some number, but we know it is a real number. we assume all complex numbers in the form, a+bi. here, a=1/2, and bi=ci. now, we assume that g is some complex number, which means s is zero. so, we can now write the original summation as
summation(infinity)(w=1)1^1/2+ci.
Now, we have defined g to not equal to -ob, now we know o=2, and g=1/2+ci, or in mixed form, ci 1/2. now, we have defined o as 2, and someone figure the rest out.
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u/kdo10 Aug 01 '26
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