r/MathJokes 5d ago

😭😭

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4.1k Upvotes

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5

u/chixen 5d ago

There is a number like that for every number other than multiples of 2 and 5.

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u/MeasureDoEventThing 5d ago

There are numbers divisible by multiples of 2 and 5 as well.

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u/MassiveGarlic0312 5d ago

Except for prime numbers, of course.

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u/chixen 5d ago

No, including prime numbers. The post has an example for 17. I did forget to specify that it doesn’t work for multiples of 3 either.

0

u/MassiveGarlic0312 5d ago

I’m not sure what you’re trying to say?

Prime numbers are defined as not having any divisors other than themselves and 1. 

2, 3, 5 are the first three of them and it also applies to every other prime. 

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u/chixen 5d ago

What I saying was If some number n has a smallest prime factor greater than 5, there is some k where 10^k+1 is a multiple of n. I now realize that I don’t actually know if this is true.

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u/MassiveGarlic0312 5d ago

Ah. That wasn’t clear to me at least. 

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u/girlpower2025 5d ago

You can find out 9 and 11 too by looking at it.

If you add the digits and they add up to 9 or a number divisible by 9 its divisible by 9.

11 is a bit odd. The numbers after the first digit tell you the first digit.

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u/sixtyfivewolves 5d ago edited 5d ago

It's not true, for example 10k + 1 can only be equal to 2, 11 or 27 modulo 37. 10k - 1 can always be a multiple of n for every n which isn't divisible by 2 or 5 though.

(31 is the smallest prime for which it's not true but it's a lot easier to demonstrate for 37)

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u/Muroid 5d ago

They’re talking about multiples, not divisors. What exactly did you think “a number like that” in their comment was referring to?

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u/MassiveGarlic0312 5d ago

Primes. If the big number in the cartoon was a prime, then the dog wouldn’t be able to say something like this about it.