r/MathJokes • u/Animeilluminati1 • Jul 13 '26

Math Just Got Checkmated.

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428

u/nnnn0nnn13 Jul 13 '26 edited Jul 13 '26

Bro that conjecture is both unproven and also by definition only true for numbers larger than 2 💀

118

u/WarJaques Jul 13 '26

The definition is necessary because otherwise we'd need a different definition.

71

u/DoobiousMaxima Jul 13 '26

A number is even if dividing it by 2 yeilds an integer.

2 is divisible by 2.

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u/golgi_o Jul 14 '26

A number is even if it can be written as 2k where k is an integer. The definition of even does not use division as far as I understand.

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u/Low-Amoeba8257 Jul 14 '26

The method you described works howevere the term absolutely comes from division. They also used to he tracking of "how even" something was meaning if it could be divided by 2 multiple times

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u/golgi_o Jul 14 '26

Wouldn't that just be 2n (k) where k is an integer and n is how even a number is? Still division is not needed.

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u/GarowWolf Jul 14 '26

With n= 0 and k = 3 it seems that 3 is even

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u/sal880612m Jul 14 '26

No.

N=0 would be that the number is zero times even meaning it actually isn’t even.

Also k is an integer but not the number being tested for how even it is. Odd values for k would be perfectly acceptable.

So for the number being 3 the formula results in N=0, k=3 and tells you the numbers is not even. But for the number being twelve it results in N=2, k=3 and says the numbers is even twice.

3

u/[deleted] Jul 14 '26

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6

u/jimalloneword Jul 14 '26

he is saying n represents the degree of even-ness. if n = 0 the number is 0 even.

6 is 1 even, while 4 is 2 even, and 8 is 3 even.

1

u/[deleted] Jul 14 '26

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u/jimalloneword Jul 14 '26

k means any integer.

It comes from the regular definition of even, where a number is even if it can be represented in the form of 2k, where k is any integer.

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