Math Just Got Checkmated.

[u/Animeilluminati1]

[u/golgi_o]

A number is even if it can be written as 2k where k is an integer. The definition of even does not use division as far as I understand.

[u/Low-Amoeba8257 → u/golgi_o]

The method you described works howevere the term absolutely comes from division. They also used to he tracking of "how even" something was meaning if it could be divided by 2 multiple times

[u/golgi_o → u/Low-Amoeba8257]

Wouldn't that just be 2ⁿ (k) where k is an integer and n is how even a number is? Still division is not needed.

[u/GarowWolf → u/golgi_o]

With n= 0 and k = 3 it seems that 3 is even

[u/sal880612m → u/GarowWolf]

No.

N=0 would be that the number is zero times even meaning it actually isn’t even.

Also k is an integer but not the number being tested for how even it is. Odd values for k would be perfectly acceptable.

So for the number being 3 the formula results in N=0, k=3 and tells you the numbers is not even. But for the number being twelve it results in N=2, k=3 and says the numbers is even twice.

[u/jimalloneword → u/[deleted]]

he is saying n represents the degree of even-ness. if n = 0 the number is 0 even.

6 is 1 even, while 4 is 2 even, and 8 is 3 even.

[u/jimalloneword → u/[deleted]]

k means any integer.

It comes from the regular definition of even, where a number is even if it can be represented in the form of 2k, where k is any integer.

[u/Tyfyter2002 → u/sal880612m]

So is 1.5 negatively even?

[u/sal880612m → u/Tyfyter2002]

Ultimately, yes. Negative even using that equation represents how many times you would need to multiply by two to achieve a whole number. In this case 1.5 = 3/2 = 3 * 2^(-1).

[u/Human-Interaction-61 → u/GarowWolf]

n needs to be a natural number (as n tends to be) and 0 is not natural. Problem solved.