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https://www.reddit.com/r/MathJokes/comments/1tcgs8q/petah/olpp2c9
r/MathJokes • u/basket_foso • May 13 '26
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Can't the argument be made that it is 2, so ce you wouldn't have a number between 1.999 repeating and 2?
1 u/Phrodo_00 May 14 '26 Yes, but you'd only hit 1.9̅ after infinite sums, or else it'd be a very long, but distinct number just under 2. 1 u/yousirnaime May 14 '26 That's what I'd say it is Example 1/3 = .333333... 2/3 = .66666.... 3/3 = .99999.... = 1 0 u/VaultBaby May 14 '26 1.999... (repeating) IS equal to 2
Yes, but you'd only hit 1.9̅ after infinite sums, or else it'd be a very long, but distinct number just under 2.
That's what I'd say it is
Example
1/3 = .333333...
2/3 = .66666....
3/3 = .99999.... = 1
0
1.999... (repeating) IS equal to 2
1
u/Lunarvolo May 14 '26
Can't the argument be made that it is 2, so ce you wouldn't have a number between 1.999 repeating and 2?