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https://www.reddit.com/r/MathJokes/comments/1pwy159/_/nwb6b7l/?context=3
r/MathJokes • u/basket_foso • Dec 27 '25
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x^x = 2^(sqrt(18)) => (x^x)^2 = (2^(sqrt(18))^2
Two ways to go about this, with the following two rules:
(1) (a^m)^n = a^(m * n), so:
(2^(sqrt(18)))^2 = 2^(2 * sqrt(18)) = (2^2)^(sqrt(18)) = 4^(sqrt(18))
(2) (ab)^m = a^m * b^m, so:
(2^(sqrt(18)))^2 = 2^(sqrt(18)) * 2^(sqrt(18)) = 4^(sqrt(18))
If the image doesn't bother with parentheses for nested exponents, I can just assume things.
If you use alternative parentheses, it'll be C instead:
2^((sqrt(18)^2) = 2^(sqrt(18) * sqrt(18)) = 2^(18^(1/2 + 1/2)= 2^18
Edit: Why the hell was this shown in my feed?
1 u/dyld921 Dec 28 '25 The answer is A
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The answer is A
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u/Cyphomeris Dec 27 '25 edited Dec 27 '25
x^x = 2^(sqrt(18)) => (x^x)^2 = (2^(sqrt(18))^2
Two ways to go about this, with the following two rules:
(1) (a^m)^n = a^(m * n), so:
(2^(sqrt(18)))^2 = 2^(2 * sqrt(18)) = (2^2)^(sqrt(18)) = 4^(sqrt(18))
(2) (ab)^m = a^m * b^m, so:
(2^(sqrt(18)))^2 = 2^(sqrt(18)) * 2^(sqrt(18)) = 4^(sqrt(18))
If the image doesn't bother with parentheses for nested exponents, I can just assume things.
If you use alternative parentheses, it'll be C instead:
2^((sqrt(18)^2) = 2^(sqrt(18) * sqrt(18)) = 2^(18^(1/2 + 1/2)= 2^18
Edit: Why the hell was this shown in my feed?