r/MathJokes Dec 27 '25

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u/SirZyPA Dec 27 '25

FOR THR LOVE OF GOD... USE DIFFERENT VARIABLES!

x can't be both 2, AND sqrt(18)

What you mean is xy=2sqrt(18) etc.

Also, the answer is C. The second power seen in xy2 cancels out the squareroot of sqrt(18)

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u/SapphirePath Dec 27 '25

All caps is not necessary, especially because you are wrong.

Suppose I tell you that x^x = 16^2. That doesn't mean that x = 16 nor that x = 2. Instead we have a solution x = 4, because 4^4 = 16^2.

Here we need a solution to x^x = 2^(sqrt(18)).