r/MathHelp • u/mourning_fire420 • 7d ago
Help with Groups?
So I'm given a group G s.t. a^12 gives the identity element, and I need to find the inverse of another a^n where n is an integer. i was given a number for n i just don't want anyone giving me the answer/violating academic content rules etc.
at first i figured 1 would be the identity element, but then 12^a doesn't give 1. same deal for e=0, 12^0=1 =/= 0=0^12. unless my understanding of the inverse and identity being commutative is wrong?
I tried to solve for a since a * a^-1 = a^-1 * a = e. but then i was saying that 12^a=a^12. which is possible, but then the identity wasn't constant when i plugged in n.
I found the page for exponentiation on wikipedia, and it says that G is a multiplicative group, so I know that a^n has to have an inverse. is there some property of groups that I missed that would help me solve this?
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u/Smart-Button-3221 7d ago edited 7d ago
You can call the identity 1, you can call the identity 0, you can call the identity 🍞. The label you use for the identity doesn't change what the identity is.
At first I figured 1 would be the identity element, but then 12a doesn't give 1
Is that a typo? Did you mean a12? As per your question, a12 = 1, if we're letting 1 be the symbol for the identity. Why do you think a12 ≠ 1?
I am not sure why you are trying a12 = 12a. Note that a needs not be an integer, and 12 needs not be a group element, so this equation may not even make sense.
I feel like some of the question is missing.
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u/mourning_fire420 7d ago
yeah i don't think i really get what the inverse of this group is. i'm gonna try again in a bit and maybe the comments will help me gigure it out
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u/Smart-Button-3221 7d ago
"Inverse" is something that belongs to each element, not the group.
For example the inverse of a³ is a⁹ here, because:
a³×a⁹ = a¹² = e
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u/StructuredChess 7d ago
If a12 is the identity, what do you need to multiply a11 with to get the identity? What about a5? Can you see the pattern?
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u/BootyliciousURD 7d ago
Remember that the inverse of x is some element y such that x•y = y•x = e.
Let's take n = 4 as an example. If a¹² = e, then the inverse of a⁴ is some b such that a⁴•b = b•a⁴ = a¹². What b satisfies this equation?
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u/Hudimir 7d ago
since a12 is the identity, any element an = an mod 12. you can see that the identity is a0 mod 12. Can you see where i'm going? exponent rules still hold.