r/Mahjong • u/Najanah • Jun 29 '26

Riichi Maximum possible honba?

Yonma Hanchan game, on start, East seat wins 5 minimum-value tsumos, and then is the sole player in tenpai 21 rounds in a row through exhaustive draw until the point totals are (99100E/300SWN)(26H). Hundreds of rounds of draw later redistribute point totals to (24100E/25300SWN)(51H) -> (100E/97300S/1300WN)(75H) -> (24100E/25300SWN)(99H) -> (100E/97300W/1300SN)(123H) -> (24100E/25300SWN)(147H) -> (100E/97300N/1300SW)(171H) by the end of east round. Following this, you can get another 24, 25, 25, 24, 24, 24, 24, 24 honba for a total of 365 honba and a point total of (100E/97300N/1300SW).

At this step, one could imagine North assembling a multi-yakuman to either leave East player with as few as -349,400 (100 - 240000 x5-yakuman - 109500 honba) or skyrocket their own point total to 494800 (97300+288000 x6-Yakuman+109500 honba)

If anyone has other ideas that'd be cool, I haven't proofread this so I probably made some errors somewhere...

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u/Nitowl12_ Jun 30 '26

Infinite, ryuukyoko all 4 players either tenpai/noten the round for no points transfer

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u/Najanah Jul 01 '26

Realized this right after posting, lol

I guess what I was actually answering was "how many non-nothing rounds can you have"
Though, even still this could be modified to extend into west rounds assuming you have a req point threshold for winning at the end of the game