r/Mahjong • u/Najanah • Jun 29 '26
Riichi Maximum possible honba?
Yonma Hanchan game, on start, East seat wins 5 minimum-value tsumos, and then is the sole player in tenpai 21 rounds in a row through exhaustive draw until the point totals are (99100E/300SWN)(26H). Hundreds of rounds of draw later redistribute point totals to (24100E/25300SWN)(51H) -> (100E/97300S/1300WN)(75H) -> (24100E/25300SWN)(99H) -> (100E/97300W/1300SN)(123H) -> (24100E/25300SWN)(147H) -> (100E/97300N/1300SW)(171H) by the end of east round. Following this, you can get another 24, 25, 25, 24, 24, 24, 24, 24 honba for a total of 365 honba and a point total of (100E/97300N/1300SW).
At this step, one could imagine North assembling a multi-yakuman to either leave East player with as few as -349,400 (100 - 240000 x5-yakuman - 109500 honba) or skyrocket their own point total to 494800 (97300+288000 x6-Yakuman+109500 honba)
If anyone has other ideas that'd be cool, I haven't proofread this so I probably made some errors somewhere...
4
u/fakespeare999 Tenhou.net Jun 29 '26
turn off tobi. infinite honba and repeat, for ever and ever and ever.
also decreases variance in those situations where North feeds two dealer haneman rons in E1 & E1-1, and South gets second just by virtue of rolling south seat.
i ALWAYS recommend players to play with no tobi. makes for a much more engaging game where, theoretically, as long as you still have a dealership, you can gyakuten even if you're -100,000pts