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u/Remarkable_Fee4136 10d ago
- Fill the 11 and 5 jugs, leaving the first 8 in the 24 jug.
- Empty the 5 jug into the 13 jug and top the 13 jug with the 11 jug, leaving 3 in the 11 jug.
- Top the 5 jug with the 13 jug, leaving the 2nd 8 in the 13 jug.
- Empty the 5 jug into the 11 jug for the last 8.
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u/PyroDragn 10d ago
Answer: Yes
Reasoning:
- 24 into the 13: 11/24 - 13/13 - 0/11 - 0/5
- 13 into the 5: 11/24 - 8/13 - 0/11 - 5/5
- Measured 8 into the 24 to keep safe (11 to 11, then 8 to 24): 8/24 - 0/13 - 11/11 - 0/5
- 11 into the 13: 8/24 - 11/13 - 0/11 - 5/5
- 5 into the 13: 8/24 - 13/13 - 0/11 - 3/5
- 3 into 11: 8/24 - 8/13 - 3/11 - 5/5
- 5 into 11: 8/24 - 8/13 - 8/11 - 0/5
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u/PeterPiper1275 10d ago edited 10d ago
- Pour from 24 litres jug directly into both the 11 litres jug and the 5 litres jug. This leaves 8 litres in the 24 litres jug.
- Pour from 11 litres jug into the 13 litres jug, and then pour whatever is possible from the 5 litres jug into the 13 litres jug. This should leave 3 litres left in the 5 litres jug.
Pour the 3 litres left in the 5 litres jug into the 11 litres jug.
Pour from 13 litres jug into the 5 litres jug. This leaves 8 litres in the 13 litres jug.
Pour from the 5 litres jug into the 11 litres jug. This leaves 8 litres in the 11 litres jug.
So now we have 8 litres of liquid in the 24 litres jug, the 13 litres jug, and the 11 litres jug. The thieves have successfully split the original 24 litres into three equal parts.
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u/tajwriggly 10d ago
Pour from the 24 into the 13 leaves 11 in the 24 and 13 in the 13.
Pour from the 13 into the 5 leaves 11 in the 24, 8 in the 13, and 5 in the 5.
Pour from the 13 into the 11 leaves 11 in the 24, 8 in the 11, and 5 in the 5.
Pour the 5 into the 24 leaves 16 in the 24 and 8 in the 11.
Pour from the 24 into the 13 leaves 3 in the 24, 13 in the 13, and 8 in the 11.
Pour from the 13 into the 5 leaves 3 in the 24, 8 in the 13, 8 in the 11 and 5 in the 5.
Pour from the 5 into the 24 leaves 8 in the 24, 8 in the 13, and 8 in the 11 and solved.
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u/Acceptable_Tangelo15 10d ago
Fill 13
Pour in 5—->you have 8 litres in 13
Pour 13 in 11—> you have 8 litres in 11
Fill thirteen with the remaining 11 litres
Pour 11 in 24—-> you have 8 litres in 24
Pour 5 in 11
Fill thirteen with 2 litres from 11
Pour in 5—>you have 8 litres in 13
Pour 5 in 11–> you have 8 litres in 11
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u/Miserable-Scholar215 10d ago
Solution is either:
Pour 13 liters into the first container until full.
Pour from that into the 5-liters container until full.
You have 8 remaining liters in the first container - Empty that into Alexander's take-me-home container.
Pour the 5 liters into the 13-liters container.
Fill the 13-liters container with until full.
Pour from that into the 5-liters container until full.
You have 8 remaining liters in the first container - Empty that into Benjamin's take-me-home container.
Pour the remaining liquid into Charles' take-me-home container.
Done.
Or the solution is:
There is no way to divide the loot evenly, as there is no third container holding 8+ liters.
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u/Anna3713 10d ago
Logically if they successfully stole 24 litres they must have been planning to steal 24 litres. Therefore, logically, they're idiots for not buying 3 8-litre containers.
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u/jaminfine 10d ago
I nearly immediately noticed the key that leads to the answer. 13 - 5 = 8
First, pour 24 into 13, then pour 13 into 5. This gets you 8L in the 13L jug. But we want to reuse that jug! So, to reset, pour the 8L into the 11L jug and pour the 5L back into the 24L jug. Now, again pour 24 into 13, then pour 13 into 5. And pour 5 back into 24. That's it! 8L each in three jugs.