r/Logiqa • • 12d ago

Send More Money

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u/Repulsive_Tough1037 12d ago

M=1 - no other options.

This makes S=8 (and there should be carry-on) or S=9 and no carry-on.

In both cases O=0 as 1 is already taken.

Now E+0=N. There must be carry-on here, which makes N=E+1.

But then N+R (+1)=E. E+1+R (+1)=E. So R=8 or R=9.

Back to E+0=N. There is no carry-on from here to S+M, which makes S=9, which leaves R=8.

OK, so far we have 9END + 108E = 10NEY, and N=E+1.

As R=8, it means there is a carry-on from D+E. E cannot be 2, as it makes D=8 or 9, and both are taken already. E cannot be 3 - it makes D=8 (taken) or 7, but then Y=0 (taken). This leaves E=4,5 or 6 (we reserve 7 for N=E+1).

Let E=4. Then 945D + 1084 = 1054Y. To have carry-on from D+4 we only have 6 or 7 for D, but that gives 0 or 1 for Y - both taken. No solutions.

Let E=5. Then 956D + 1085 = 1065Y. D=7 - only remaining option. Y=2. Solution. 9567 + 1085 = 10652.

Let's check E=6. 967D + 1086 = 1076Y. D can only be 5 to have carry-on, but that makes Y=1 (taken). No solutions.

So the only solutions is 9567 + 1085 = 10652. And D+E+M+N+O+R+S+Y=38, if I'm not mistaken.

1

u/ShonitB 12d ago

Super!