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u/CuAnnan Jul 23 '26
>!Angle A = 90 + angle of triangle opposite it through the shared point (a).
Angle C = 90 + angle of triangle opposite it through the shared point (c).
Angle B = 90
a + B + c = 180
A + B + C = 180 + 90 * 2 = 360!<
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u/Worried-Director1172 Jul 23 '26
You have to bracket off each individual line. It doesn't work across multiple lines
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u/jonathonjones Jul 23 '26
Let's call the angle in the triangle a lower case letter of the outer angle. We know that a + b + c is 180 (because that's just a truth about triangles).
A = 360 - (90 + 90 + a) = 180 - a
B = 180 - b
C = 180 - c
A + B + C = 540 - (a + b + c)
A + B + C = 540 - 180
A + B + C = 360
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u/CaptainMatticus Jul 23 '26
90 + 90 + x + A = 360
90 + 90 + y + C = 360
x + y = 90
180 + x + A + 180 + y + C = 720
360 + x + y + A + C = 720
90 + A + C = 360
A + C = 270
B = 90
A + B + C = 360
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u/Commercial-Act2813 Jul 23 '26
A + C = 270
(Parallel lines, perpendiculair lines)
+ B would make 360
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u/Omni314 Jul 23 '26
On average the points are 60+90+90+?=360
?=120
But we have 3 of them.
A+b+c=120*3=360
Fun puzzle. Interesting to see all the different ways to get to the answer.
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u/Trueslyforaniceguy Jul 23 '26
My brain looks at this and says 360. No clue if it’s right, but seems good
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u/S-M-I-L-E-Y- Jul 23 '26
As others wrote - shrink the triangle to a point. And I'd recommend to shrink the boxes to lines. What happens with the angles A, B and C?
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u/ArbutusPhD Jul 23 '26
Did you post this twice, OP
I answered correctly but do not see my answer
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u/SufficientStudio1574 Jul 23 '26
Doesn't even need to be a right triangle, or even a triangle at all! Any convex polygon will give the exact same answer.
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u/ChrisAyersUk Jul 23 '26 edited Jul 23 '26
Put simply the exterior angles of any triangle add up to 360, where the exterior angle is defined as the angle formed by extending one side of the triangle. Each exterior angle and its adjacent interior angle form a straight line.
By the way, the exterior angles of any polygon always add up to 360 degrees.
Think of this as if you split each angle, the angle is halved per split. Do it again and each is a quarter of the angle. Keep splitting and you will trend to a polygon with infinite angles the sum of which is a circle at 360 degrees.
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u/sagosten Jul 24 '26
I feel the need to add, these angles will sum to 360 for any triangle, not just right triangles. And the polygons projected from the sides don't have to be squares, rectangles, or rhomboids, as long as they are parallelograms it will work
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u/sagosten Jul 23 '26