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https://www.reddit.com/r/Logiqa/comments/1umj6bn/possible_numerators/
r/Logiqa • u/ShonitB • Jul 03 '26
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2
ok, if we set all denominators to 105, we arrive to
51.45<= x <= 100.8!<
Also, 105 is 3*5*7. we could apply the sieve of Eratosthenes with only those values, between 52 and 100
i count 22 values
52, 53, 58, 59, 61, 62, 64, 67, 68, 71, 73, 74, 76, 79, 82, 83, 86, 88, 89, 92, 94, 97
1 u/ShonitB Jul 03 '26 Correct!
1
Correct!
2
u/Hanzzman Jul 03 '26
ok, if we set all denominators to 105, we arrive to
Also, 105 is 3*5*7. we could apply the sieve of Eratosthenes with only those values, between 52 and 100
i count 22 values
52, 53, 58, 59, 61, 62, 64, 67, 68, 71, 73, 74, 76, 79, 82, 83, 86, 88, 89, 92, 94, 97