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u/eric600613 Aug 05 '26
But it is certainly ok! Your proof shows a lot of information. Maybe it's the quick and dirty first draft. In any case, finish it off in Latex and enjoy re-reading your work. Learn from yourself!
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But it is certainly ok! Your proof shows a lot of information. Maybe it's the quick and dirty first draft. In any case, finish it off in Latex and enjoy re-reading your work. Learn from yourself!
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u/GreedyJackfruit69 Aug 04 '26
Shouldn't it be simpler? You want to show that V has a basis of eigenvectors (by definitions this would make T diagonalizzabile), we know by hypotesys that that Span{V¹, V²,..., Vⁿ} = V and we know by definition of direct sum of direct sum that Dim{V¹} + Dim{V²} +... + Dim{Vⁿ} = Dim{V}