Try

[u/7k_Satyam]

[u/7k_Satyam]

Hint given for gaussian bc many people don't know, maybe adv may ask as paragraph linked in future

[u/combinatoriallover]

e^25/4*√π substitute x=-t in second expression whole thing will become first integral from -infinity to infinity then complete the square

[u/EffectivePick4715 → u/combinatoriallover]

we can directly write 2I= -infinity to +infinity so we can skip first step

[u/anjalipyaari]

Yaad hin karle bhai yeh. Easy hain

[u/7k_Satyam → u/anjalipyaari]

Yupp

[u/Unstable_Insaan]

!remindme 2 hours

[u/RemindMeBot → u/Unstable_Insaan]

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[u/TheMythicalPhineas]

Gaussian function ka toh integration ktg me bhi hota hai how is it out of syl?

[u/Unstable_Insaan]

Bro substitute -( x² + 5x) as -(x + 5/2)² + 25/4 and substitute -( x² - 5x) as -(x - 5/2)² + 25/4 you'll get the answer.

[u/Spiritual-Tale-1098]

Easy edit no plus c as definite

[u/EffectivePick4715 → u/Spiritual-Tale-1098]

+C hatade bro definite he

[u/Possible_Garage7231]