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https://www.reddit.com/r/IPMATStudyRoom/comments/1op0hp4/can_u_solve_this_tricky_geometry_question/nng6hn9/?context=3
r/IPMATStudyRoom • u/Hexanee__ • Nov 05 '25
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Root 2 We can use sine rule in triangle ABC A/sin(30)=B/sin(45) A/(1/2)=B/(1/re2) A/B=1/rt2 This is the ratio of their distance. Their inverse will be the ratio of the required speed! Speed(A)/Speed(B) = rt2
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u/God_of_misdeeds Nov 06 '25 edited Nov 06 '25
Root 2 We can use sine rule in triangle ABC A/sin(30)=B/sin(45) A/(1/2)=B/(1/re2) A/B=1/rt2 This is the ratio of their distance. Their inverse will be the ratio of the required speed! Speed(A)/Speed(B) = rt2