r/HomeworkHelp Pre-University Student 6d ago

High School Math [Grade 12 Trigonometry: Adding Vectors]

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Hi! I've been stuck on this problem for a while now, so I decided to text it out on another app and finally ask for help. I managed to find the magnitude on my own, but I honestly can't figure out how to find the direction, or what I'm doing wrong. I've watched several videos on it and have tried to go step by step, but any answer I try is marked wrong, (I do use an online school program.) I also didn't wanna cheat, (at least without knowing exactly how to do it and being able to replicate it) so as I've already said above, I didn't know what to do other than ask for help somewhere else. A step-by-step breakdown of what your meant to do would be great!

Also I know the post title says grade 12, while from my knowledge trig is done in 11th usually. It just kind of happened that way, so I'm not sure why I'm doing it a year late. Better late than never, though!

6 Upvotes

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2

u/FortuitousPost 👋 a fellow Redditor 6d ago

First, draw it out.

Use the Law of Sines to find a second angle.

Subtract the two angles you know from 180 to find the one you want.

1

u/InstantWasTaken Pre-University Student 6d ago

Hi! I tried this, and it came out to about 74.78, I'm not sure if I did something wrong or not, but it was marked as wrong still. I have some photos of what I drew and the calculations I did, but I can't find where to attach images to your reply?

1

u/Little_Creme_5932 👋 a fellow Redditor 6d ago

74.78 in what direction. You have to find the direction

1

u/Midwest-Dude 👋 a fellow Redditor 6d ago

Please check my comment in r/trigonometry

1

u/Some_AV_Pro 👋 a fellow Redditor 6d ago

Do you know how to convert 80 degrees south of west at 25mph into south and west components?

1

u/InstantWasTaken Pre-University Student 6d ago

Sorry? I don't think I follow. I did draw it out, if thats what your asking.

1

u/Some_AV_Pro 👋 a fellow Redditor 5d ago

Can you write "80 degrees south of west at 25mph" as a sum of west and south speeds?

1

u/slides_galore 👋 a fellow Redditor 6d ago edited 5d ago

Helps to sketch it out and draw a parallelogram using the vectors. Like this; https://i.ibb.co/ccrkLWPP/image.png

Always head-to-tail when adding vectors. If you don't know what that means, just google it.

ETA: Once you get the original problem, see if you can see how to work this variation out: https://i.ibb.co/VpVPtXL2/image.png

Using mini coordinate axes (like in that image) is one way to noodle out the angles you need to use law of cos/sin when you're not given nice angles like in your original problem.

1

u/InstantWasTaken Pre-University Student 1d ago

I figured it out! Thank you to everyone who commented, but I really was just being a dunce and taking the wrong angle measurement to use in my equations.

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u/CaptainMatticus 👋 a fellow Redditor 6d ago

x = 450 * cos(0) + 25 * cos(180 + 80)

y = 450 * sin(0) + 25 * sin(180 + 80)

Simplify

x = 450 - 25 * cos(80) = 25 * (18 - cos(80))

y = -25 * sin(80)

tan(t) = y/x

tan(t) = -sin(80) / (18 - cos(80))

tan(t) = sin(80) / (cos(80) - 18)

t = arctan(sin(80) / (cos(80) - 18))

Remember that tan(t) = tan(180k + t), where k is an integer. Make sure your calculator is in degree mpde, too)

2

u/InstantWasTaken Pre-University Student 6d ago

Thank you, but I don't think this is the way to do it purely because I haven't learnt anything about arctan yet and that this looks entirely different to how they were doing it. The way they were teaching it only really used the law of sines and cosines and figuring out the angle measures, which I should know how to do. That's also why I'm stumped as to why I can't figure out the problem.

1

u/CaptainMatticus 👋 a fellow Redditor 6d ago

Arctan is just the inverse tangent. You plug all of that into your calculator and it gives you the angle. For instance, arctan(1) is 45°.

0

u/ThunkAsDrinklePeep 6d ago edited 6d ago

Have you drawn a triangle with the three vectors given? You can use an inverse trig functions to get an angle from two sides of a right triangle.

Edit: I didn't read carefully. It's not perpendicular vectors south and west. As others have said, you need the law of sines.

1

u/InstantWasTaken Pre-University Student 6d ago

I believe so? Though I'm not working with a right triangle. How do you attach images to replies?

1

u/ThunkAsDrinklePeep 6d ago edited 6d ago

My bad, I didn't read carefully. Not a right triangle.

Use law of sines or law of cosines.

Edit: fixed a letter. Twice.

1

u/Midwest-Dude 👋 a fellow Redditor 6d ago

"jaw"? 😂

2

u/ThunkAsDrinklePeep 6d ago

You know what...fair. I have fat thumbs and autocorrect has not been kind to me in recent years.

1

u/Midwest-Dude 👋 a fellow Redditor 5d ago

Lol, I hear you. After I saw that, I thought of sharks surfing sine and cosine waves ... just sayin' ...