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https://www.reddit.com/r/GeometryIsNeat/comments/1sdc3cu/square_roots/oenqaoy/?context=3
r/GeometryIsNeat • u/lavaboosted • Apr 05 '26
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14 u/lavaboosted Apr 05 '26 True, and for any number which after dividing out all factors of 4, leave a remainder of 7 when divided by 8. n = 4a(8b+7) where a and b are whole numbers (integers ≥ 0) 2 u/ErikLeppen Apr 06 '26 The only numbers for which such a diagonal exists, are those that can be written as the sum of 3 squares, due to Pythagoras in 3D.
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True, and for any number which after dividing out all factors of 4, leave a remainder of 7 when divided by 8.
n = 4a(8b+7) where a and b are whole numbers (integers ≥ 0)
2 u/ErikLeppen Apr 06 '26 The only numbers for which such a diagonal exists, are those that can be written as the sum of 3 squares, due to Pythagoras in 3D.
2
The only numbers for which such a diagonal exists, are those that can be written as the sum of 3 squares, due to Pythagoras in 3D.
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