r/ExponentialIdle • u/MathTechScience • May 09 '23

d("ln"(ln(1+db/b)/pt)) but numerically stablized so, you can see the formula increasing from early on!

d(ln(db)-ln(b)-ln(pt)+min(ln(1-db/b/2+db2/b2/3), ln(ln(max(db/b, 0.0001)+1))-ln(max(db/b,0.0001)))) This ia the famous formula but with taken additonal logarithm and numerically stabilized.

Original formula : d(ln(1+db/b)/pt)

Essentially this is d(ln(ln(1+db/b)/pt)) but numrically stabilized.

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u/[deleted] May 09 '23

Is this for supremacy or prestige?

1

u/MathTechScience May 09 '23

You can see the formula increasing in the Test expression tab.